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rewona [7]
3 years ago
11

Consider the function f(x) = 4x² - x + 3. What is f(1)?

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
3 0

Replace every x you see in the function with 1 and simplify.

Let x be 1.

f(1) = 4(1)^2 -(1) + 3

f(1) = 4(1) - 1 + 3

f(1) = 4 - 1 + 3

f(1) = 3 + 3

f(1) = 6

Done!

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Temka [501]
No because you count L then M then J and lastly K. Therefore it is incorrect.
7 0
4 years ago
Read 2 more answers
Hello please help help
irinina [24]

9514 1404 393

Answer:

  48°

Step-by-step explanation:

ΔACB is isosceles, so angles A and B have the same measure. The measure of angle C in that triangle is ...

  ∠C = 180° -2(69°) = 42°

Angle C in ΔCDE has the same measure. Angle D is the complement of that:

  ∠D = 90° -42° = 48°

_____

The relations we used are ...

  • the sum of angles in a triangle is 180°
  • base angles of an isosceles triangle are congruent
  • vertical angles are congruent
  • acute angles in a right triangle are complementary
5 0
3 years ago
Consider all 5 letter "words" made from the full English alphabet. (a) How many of these words are there total? (b) How many of
VARVARA [1.3K]

Answer:

a) There are 11,881,336 of these words in total.

b) There are 7,893,600 of these words with no repeated letters.

c) 896,376 of these words start with an a or end with a z or both

Step-by-step explanation:

Our words have the following format:

L1 - L2 - L3 - L4 - L5

In which L1 is the first letter, L2 the second letter, etc...

There are 26 letters in the English alphabet.

(a) How many of these words are there total?

Each of L1, L2, L3, L4 and L5 have 26 possible options.

So there are 26^{5} = 11,881,336 of these words total

(b) How many of these words contain no repeated letters?

The first letter can be any of them, so L1 = 26.

At the second letter, the first one cannot be repeated, so L2 = L1 - 1 = 25.

At the third letter, nor the first nor the second one can be repeated, so L3 = L1 - 2 = 24

This logic applies until L5

So we have

26-25-24-23-22

In total there are

26*25*24*23*22 = 7,893,600

of these words with no repeated letters.

(c) How many of these words start with an a or end with a z or both (repeated letters are allowed)?

T = T_{1} + T_{2} + T_{3}

T_{1} is the number of words that start with an a and do not end with z. So we have

1 - 26 - 26 - 26 - 25

The first letter can only be a, and the last one cannot be z. So:

T_{1} = 26^{3}*25 = 439,400

T_{2} is the number of words that start with any letter other than a and end with z. So we have

25 - 26 - 26 - 25 - 1

The first letter can be any of them, other than a, and the last can only be z. So:

T_{2} = 26^{3}*25 = 439,400

T_{3} is the number of words that both start with a and end with z. So:

1 - 26 - 26 - 26 - 1

The first letter can only be a, and the last can only be z. The other three letters could be anything. So:

T_{3} = 26^{3} = 17,576

T = T_{1} + T_{2} + T_{3} = 2*439,400 + 17,576 = 896,376

896,376 of these words start with an a or end with a z or both

4 0
3 years ago
Ashin has been working in UAE for a decade and saved AED 125,500 which he wants to transfer now to his parent's account in India
saul85 [17]

Answer:

2510000 INR

Step-by-step explanation:

Given

Savings = AED 125500

1\ AED =20\ INR

Required

The amount that will be withdrawn in India

We have:

1\ AED =20\ INR

Multiply both sides by the savings

125500 * 1\ AED =20\ INR * 125500

125500\ AED =125500 * 20\ INR

So, we have:

125500\ AED =2510000\ INR

<em>Hence, the amount that will b withdrawn is: 2510000 INR </em>

3 0
3 years ago
Jack has a cat that is 4 times as large as jill's cat. combined, both cats weigh 35 pounds. how much does jacks cat weigh ?
Sever21 [200]
If we say that the weight of Jill's cat is w, then we can say that the weight of Jack's cat is 4w.

We know that the combined weight is 35 pounds, so we can write this as

4w+w=35

Which simplifies to

5w=35

If we divide by 5, we are left with

w=7

So that gives us the weight of Jill's cat. If Jack's cat weighs 4 times as much, we can see that

4x7=28

Therefore, Jack's cat weighs 28 pounds :)
7 0
4 years ago
Read 2 more answers
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