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Elena L [17]
3 years ago
7

Does anyone understand this

Mathematics
1 answer:
Nataliya [291]3 years ago
3 0

For this problem, 0.25 in = 50 m. So

11 in = (11 in) • (50/0.25 m/in) = 2200 m

Alternatively, if 0.25 in = 50 m, that means 1 in = 200 m. So 11 in = 11 (200 m) = 2200 m.

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The lengths of pregnancies in a small rural village are normally distributed with a mean of 262 days and a standard deviation of
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The range in which we can expect to find the middle 68% of most pregnancies is [245 days , 279 days].

Step-by-step explanation:

We are given that the lengths of pregnancies in a small rural village are normally distributed with a mean of 262 days and a standard deviation of 17 days.

Let X = <u><em>lengths of pregnancies in a small rural village</em></u>

SO, X ~ Normal(\mu=262,\sigma^{2} = 17^{2})

Here, \mu = population mean = 262 days

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<u>Now, the 68-95-99.7 rule states that;</u>

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So, middle 68% of most pregnancies is represented through the range of within one standard deviation points, that is;

[ \mu -\sigma , \mu + \sigma ]  =  [262 - 17 , 262 + 17]

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Hence, the range in which we can expect to find the middle 68% of most pregnancies is [245 days , 279 days].

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Divide 42/-8 <br><br> Please help! :)
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Find the time, in years, needed for the turtle population described by the
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