In place of t, or theta, I'm going to utilize x instead. So the equation is -3*cos(x) = 1. Get everything to one side and we have -3*cos(x)-1 = 0
Let f(x) = -3*cos(x)-1. The goal is to find the root of f(x) in the interval [0, 2pi]
I'm using the program GeoGebra to get the task done of finding the roots. In this case, there are 2 roots and they are marked by the points A and B in the attachment shown
A = (1.91, 0)
B = (4.37, 0)
So the two solutions for theta are
theta = 1.91 radians
theta = 4.37 radians
60=4x+24
-24. -24
36=4x
36÷4
x= 9
she needs babysit 9 more hours to have enough for the bool series
Answer:
y=-4, x=1
Step-by-step explanation:
2x-y=6 x+y=-3
2(-3-y)-y=6 x=-3-y
-6-2y-y=6 x=-3+4
-3y=12 x=1
y=-4
Consider this option (this is not the only way):
1. according to the condition 2345N is divisible by <em>6</em>, it means, that N is even number (0;2;4;6 or 8).
2. <em>6</em>=3*2, then the number 2345N is divisible by 3 also. It means, that the number (2+3+4+5+N)=(14+N) is divisible by 3, where N={0|2|4|6|8}.
3. using items 1 and 2:
(14+4)=18; only 18 is divided by 3, it means that N=4.
answer: 4.
Note also, that only 23451; 23454 and 23457 are divided by 3. Only 2345<u>4</u> is divided by 6 (2345<u>4</u>/6=3909).
Answer:
Step-by-step explanation:
Did you ever figure it out? I need help with this as well.