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creativ13 [48]
3 years ago
7

How many solutions does y = 3x - 5 and 6x - 2y = 10 has?

Mathematics
1 answer:
Basile [38]3 years ago
6 0

Answer:

I think it d infinitely many solutions

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What's the answer ?
Fittoniya [83]
The answer would be C.   
3 0
3 years ago
An AP consists of 55 terms of which 5th term is 14 and last term is 144. Find the 29th term
Stels [109]

Answer:

29th term = 76.4

Step-by-step explanation:

Total terms = 55

aₙ = a + (n - 1) d

5th term = a₅ = 14

   a + (5 - 1)*d = 14

   a + 4d = 14  --------------------(I)

last term = a₅₅ = 144

               a + (55 - 1)d = 144

      a + 54d = 144----------------(II)

Multiply equation (II) by (-1)

(I)             a +  4d = 14

(II)*(-1)     <u>-a - 54d = -144</u>  {Now add and thus a will be eliminated}

                   -50d = -130

 d = -130/-50

d = 2.6

Plug in d = 2.6 in equation (I)

a + 4* 2.6 = 14

  a  + 10.4 = 14

              a = 14 - 10.4

              a = 3.6

29th term = a₂₉ =  3.6 + (29 - 1)* 2.6

                          = 3.6 + 28* 2.6

                          = 3.6 + 72.8

                     a₂₉ =  76.4

3 0
3 years ago
Read 2 more answers
Let's say you have this data: 25, 26, 24, 26, 25, 7, 8, 8, 15, 10, 25, 24, 26 What should your bin size be if you want to have 1
Arte-miy333 [17]
Your bin size should be 2
8 0
3 years ago
Twenty-five percent of the data falls below what number?
pychu [463]

Answer:

60 is the best answer for this question

3 0
3 years ago
LL
Sonbull [250]

Answer:

x=\boxed{6.6}

\overline{\sf DE}=\boxed{13.2}\:\:\sf units

Step-by-step explanation:

<u>Geometric Mean Theorem - Altitude Rule</u>

The <u>altitude</u> drawn from the vertex of the right angle perpendicular to the hypotenuse separates the <u>hypotenuse</u> into <u>two segments</u>.  The ratio of one segment to the altitude is equal to the ratio of the altitude to the other segment:

\sf \dfrac{segment\:1}{altitude}=\dfrac{altitude}{segment\:2}

From inspection of the given diagram:

  • altitude = FD = 9
  • segment 1 = CD = 5
  • segment 2 = DE = 2x+3

\begin{aligned}\sf \dfrac{segment\:1}{altitude} & = \sf \dfrac{altitude}{segment\:2}\\\\\implies \dfrac{5}{9} & = \dfrac{9}{2x+3}\\\\5(2x+3) & = 81\\\\10x+15 & = 81\\\\10x & = 66\\\\ \implies x & = 6.6\end{aligned}

Substitute the found value of x into the expression for DE:

\begin{aligned}\sf \overline{DE} & = 2x+3\\\implies \sf \overline{DE} & = 2(6.6)+3\\& = 13.2+3\\& =16.2\:\: \sf units\end{aligned}

5 0
2 years ago
Read 2 more answers
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