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Anton [14]
3 years ago
9

Can a rational number to a rational power be rational

Mathematics
1 answer:
Aleks [24]3 years ago
8 0

Answer:

it is possible to get something rational.

Step-by-step explanation:

This can't really be explained.

You might be interested in
A tower stand on a horizontal plane. P is the top and Q is the bottom of the tower. A and B are two points on this plane such th
pochemuha

Answer:

32√5

Step-by-step explanation:

We have the right triangles PQA and PQB as well as the given right triangle QAB.

cot(PAQ) = 2/5 = QA/PQ

cot(PBQ) = 3/5 = QB/PQ

cot(PAQ) / cot(PBQ) = (2/5) / (3/5) = 2/3

cot(PAQ) / cot(PBQ) = (QA/PQ) / (QB/PQ) = QA / QB

QA / QB = 2/3

QA = (2/3) QB

QB = (3/2) QA

By the Pythagorean Theorem we have:

(QA)² + 32² = (QB)²

(QA)² + 32² = (3/2 QA)²

(QA)² + 1024 = (9/4) (QA)²

(5/4) (QA)² = 1024

(QA)² = (4/5)1024 = 4096/5

QA = 64/√5

Solve for PQ.

cot(PAQ) = QA/PQ

PQ = QA / cot(PAQ)

PQ = (64/√5) / (2/5) = 32√5

The height of the tower is 32√5.

7 0
4 years ago
PLEASE HELP !! I'LL GIVE YOU BRAINLIEST !!
Marizza181 [45]
Sorry but, there’s nothing attached so I can not help you.
3 0
3 years ago
Read 2 more answers
The graph shows a line and two similar triangles.
docker41 [41]

Answer:

y=1/3x+2

Step-by-step explanation:

7 0
3 years ago
What is 50 percent of 18?
Effectus [21]
Steps:
18*0.5=9

Answer:

9
3 0
2 years ago
Read 2 more answers
You have 800 feet of fencing and you want to make two fenced in enclosures by splitting one enclosure in half. What are the larg
katovenus [111]
Problema Solution

You have 800 feet of fencing and you want to make two fenced in enclosures by splitting one enclosure in half. What are the largest dimensions of this enclosure that you could build?

Answer provided by our tutors

Make a drawing and denote:


x = half of the length of the enclosure


2x = the length of the enclosure


y = the width of the enclosure


P = 800 ft the perimeter


The perimeter of the two enclosures can be expressed P = 4x + 2y thus


4x + 3y = 800


Solving for y:

........

click here to see all the equation solution steps

........

y = 800/3 - 4x/3


The area of the two enclosure is A = 2xy.


Substituting y = 800/3 - 4x/3 in A = 2xy we get


A = 2x(800/3 - 4x/3)


A =1600x/3 - 8x^2/3


We need to find the x for which the parabolic function A = (- 8/3)x^2 + (1600/3)x has maximum: 


x max = -b/2a, a = (-8/3), b = 1600/3


x max = (-1600/3)/(2*(-8/3))


x max = 100 ft


y = 800/3 - 4*100/3


y = 133.33 ft


2x = 2*100


2x = 200 ft

3 0
3 years ago
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