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Allushta [10]
2 years ago
15

Please help me please please

Mathematics
1 answer:
Mumz [18]2 years ago
8 0

Answer:

x - 4 = 0

Step-by-step explanation:

Slope is undefined

So, slope m = 1/0

Line is passing through the point (4, 8)

Equation of line:

y -  y_{1} = m(x - x_{1} ) \\  \\ (y -  8 )=  \frac{1}{0} (x - 4) \\  \\ (y -  8 ) \times 0=  (x - 4) \\  \\ 0 = x - 4 \\  \\ x - 4 = 0 \:  \\ is \: the \: required \: equation \:  \\ line.

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Which equation has a value greater than -6 and less than 15?​
valkas [14]

Answer:

I belive it would be D

Step-by-step explanation:

8 0
3 years ago
One number added to three times another number is 24. Five times the first number added to three times the other number is 36. F
Lera25 [3.4K]
Okay, so the equations would be:
x + 3y = 24
3y + 5x = 36

Imma use Substitution to solve this:
x = -3y + 24

3y + 5(-3y + 24) = 36
3y - 15y + 120 = 36
-12y + 120 = 36
-12y = -84
y = 7

x = -3(7) + 24
x = -21 + 24
x = 3

So the first number (x) would be 3 and the second number (y) would be 7.
5 0
3 years ago
A block of cheese is in the shape of a rectangle prism with a width of 2.5 inches in the height of 5 inches the volume of the bl
brilliants [131]
The formula for volume is l x w x h.

To find the missing link, we do the equation backwards.

l x 2.5 x 5 = 75

If we divide 75 by 5 then by 2.5, we get 6 which becomes our length.

To check, do 5 x 2.5 x 6 which should equal 75 

6 is your length
5 0
3 years ago
Read 2 more answers
Please help. linear equations.
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8 0
3 years ago
An artificial lake is in the shape of a rectangle and has an area of 9/20 square mile the width of the lake is 1/5 the length of
DIA [1.3K]
Answer:  The dimensions are:   " 1.5 mi.  ×  ³⁄₁₀  mi. " .
_______________________________________________
             { length = 1.5 mi. ;  width =  ³⁄₁₀  mi. } .
________________________________________________
Explanation:
___________________________________________
Area of a rectangle:

A = L * w ; 

in which:  A = Area = (9/20) mi.² ,
                L = Length = ?
                w = width = (1/5)*L = (L/5) = ?
________________________________________
  A = L * w ;  we want to find the dimensions; that is, the values for
                         "Length (L)"  and "width (w)" ; 
_______________________________________
Plug in our given values:
_______________________________________
 (9/20) mi.² = L * (L/5) ;  in which: "w = L/5" ; 
 
     → (9/20) = (L/1) * (L/5) = (L*L)/(1*5) = L² / 5 ;
   
          ↔  L² / 5  = 9/20 ;
 
            →  (L² * ? / 5 * ?) = 9/20 ?    

                →     20÷5 = 4 ;  so; L² *4 = 9 ;
 
                   ↔    4 L² = 9 ; 
 
                   →  Divide EACH side of the equation by "4" ;
           
                   →   (4 L²) / 4 = 9/4 ;
______________________________________
           to get:  →  L² = 9/4 ; 
 Take the POSITIVE square root of each side of the equation; to isolate "L" on one side of the equation; and to solve for "L" ;
___________________________________________          
 
     →   ⁺√(L²)   =   ⁺√(9/4) ;

    →   L  =  (√9) / (√4) ; 

    →  L = 3/2 ; 

    → w = L/5 = (3/2) ÷ 5 = 3/2 ÷ (5/1) = (3/2) * (1/5) = (3*1)/(2*5) = 3/10;
________________________________________________________
Let us check our answers:
_______________________________________
(3/2 mi.) * (3/10 mi.) =? (9/20) mi.² ??

→ (3/2)mi. * (3/10)mi.  =  (3*3)/(2*10) mi.² = 9/20 mi.² ! Yes!
______________________________________________________
So the dimensions are: 

Length = (3/2) mi. ;  write as: 1.5 mi.

width = ³⁄₁₀ mi.
___________________________________________________
or; write as:  " 1.5 mi.  ×  ³⁄₁₀ mi. " .
___________________________________________________
7 0
3 years ago
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