Factor 28 and 49
28
1*14
1*2*7
49
7*7
7 is the answer
Answer: 11 year
P(1) = 37,100
P(4) = 58,400
The linear equation (for x ≥ 1)
P(x) = 37,100 + a(x-1)
For x = 4
58,400 = 37,100 + a(4-1)
58,400 - 37,100 = 3a
21300 = 3a
a = 7100
So, the linear equation:
P(x) = 37100 + 7100*(x-1)
P(x) = 37100 + 7100x - 7,100
P(x) = 7100x + 30000
To find when the profit should reach 108100, we can substitute P(x) by 108100.
108100 = 7100x + 30000
108100 - 30000 = 7100x
78100 = 7100x
x = 78100/7100
x = 11
Answer: 11 year
9514 1404 393
Answer:
x = 5, x = 11
Step-by-step explanation:
Set f(x) = 0 and solve for x.
0 = (x -8)² -9
9 = (x -8)² . . . . . add 9
±√9 = x -8 . . . . . take the square root
±3 +8 = x . . . . . . . add 8
That is, ...
x = 8 -3 = 5 . . . . lesser x
x = 8 +3 = 11 . . . greater x