let's recall that the vertical asymptotes for a rational expression occur when the denominator is at 0, so let's zero out this one and check.
Answer:
Step-by-step explanation:
It wanted to be reduced
Answer:
3.9984i-3.0021j
Step-by-step explanation:
Due to the fact that we are only asked for the components on A, we will focus on that information.
The first thing we need to do is to dimension the magnitud of A as a hypotenuse of a right triangle. As the vector is ponting in south-east direction, we can asume that it´s (i) component will be positive and it´s (j) component will be negative.
Now, using trigonometric functions we can find the components of the vector A by multiplying the magnitude by -sin(x) for (j) and cos(x) for (i).
-5sin(36.9)=-3.0021
(this component is negative due to the fact that the vector is pointing down)
5cos(36.9)= 3.9984
Now we write in the correct notation x(i) + y(j)
3.9984i-3.0021j
Answer:
B
Step-by-step explanation:
"You're making me uncomfortable. Please stop" is the most professional response
Answer:
I(x) = 12x² + 8x + 5
Step-by-step explanation:
* Lets talk about the solution
- P(x) is a quadratic function represented graphically by a parabola
- The general form of the quadratic function is f(x) = ax² + bx + c,
where a is the coefficient of x² and b is the coefficient of x and c is
the y-intercept
- To find I(x) from P(x) change each x in P by 2x
∵ P(x) is dilated to I(x) by change x by 2x
∵ I(x) = P(2x)
∵ P(x) = 3x² + 4x + 5
∴ I(x) = 3(2x)² + 4(2x) + 5 ⇒ simplify
∵ (2x)² = (2)² × (x)² = 4 × x² = 4x²
∵ 4(2x) = 8x
∴ I(x) = 3(4x²) + 8x + 5
∵ 3(4x²) = 12x²
∴ I(x) = 12x² + 8x + 5
