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3 years ago

Is 36z^2 - 9 a difference of squares?

Mathematics

1 answer:

Dvinal [7]3 years ago

4 0

Answer:

yes

Step-by-step explanation:

A difference of squares has the form a² - b² = (a - b)(a + b)

note that 36z² = (6z)² ⇒ a = 6z and 9 = 3² ⇒ b = 3

36z² - 9 is a difference of squares and factors as (6z - 3)(6z + 3)

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What is the answer to −9p − 6 = −141

Daniel [21]

Answer:

p = 15

Hope this helps

Step-by-step explanation:

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3 years ago

Read 2 more answers

Determine if the lines are parallel, perpendicular, or neither 10x+5y=-5 and y=-2x+6

Ksenya-84 [330]

If they are parallel they will have the same slope , m

So in y = mx + c, if there are two equations which both have the same m value they will be parallel.
If the lines are perpendicular they'll have slopes like this: 1/2 to -2/1 - where they flip and a negative gets added.

In the equations: 10x + 5y = -5 , and y = -2x + 6
We can rearrange 10x + 5y = -5 to be in the form y = mx + c
10x + 5y = -5
5y = -5 - 10x
y = -1 - 2x
y = -2x - 1

Since y = -2x - 1 and y = -2x + 6 both have the same slope of -2 they are parallel!

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4 years ago

Write an equivalent fraction for 10/2

Scorpion4ik [409]

10/2 is an improper fraction. So, change it to a mixed number. 10÷2=5

5 is the mixed number and is the equivalent fraction. You can also do 5/1 which is also equivalent.

7 0

3 years ago

Name two solutions for each inequality.

ahrayia [7]

So,

#1: $n \geq 3 \frac{11}{16} + 4 \frac{1}{2}$

Convert to like improper fractions.
$n \geq \frac{59}{16} + \frac{72}{16}$

Add.
$n \geq \frac{131}{16}\ or\ 8 \frac{3}{16}$

So, one solution could be $8 \frac{3}{16}$ .

Another solution could by 9. There is also 10, 11, 12, etc., and all numbers in between.

#2: $k \ \textless \ 6 \frac{2}{5} * 15$

Convert into improper fraction form.
$k \ \textless \ \frac{32}{5} * 15$

Multiply.
$\frac{(2^5)(3)(5)}{5}$

Cross-cancel, and we have our final result.
$(2^5)(3) = 96$
k < 96

96 is not a solution.

95 is a solution.

So is 94, 93, 92, etc, and all numbers in between.

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3 years ago

What is the remainder when x^3 -1 is divided by (x+2)

Gnom [1K]

Answer:

Use m athway

Step-by-step explanation:

6 0

3 years ago