Here his a link to how you solve this , please do not use it to cheat but to learn from it
http://ecsd-fl.schoolloop.com/file/1298972684338/1298972684200/3666926465936506857.pdf
Hope this helps !<span />
The exponential equation for the growth is f(x)=57
where x is the number of days and the population on 21st march is 2069983.5 of microbes.
Given:
Days population
0 57
1 95
5 700
10 8525
We have to form exponential equation which shows the growth of microbes.
We know that exponential equation which shows the sum is as under:
f(x)=P
where r is the rate of growth and x is the number of days, months or years depending on how things grows.
In the question when x=0 population is 57.
f(0)=57
P
=57
P=57
When x=1, population is 95.
f(1)=95
P
=95
57
=95
57=95/
----1
when x=5,population is 700.
f(5)=700
P
=700
57
=700
57=700/
-----2
Equating 1&2
95/
=700/

=7.36
=7.36
=
equating both sides
4r=2
r=0.5
put the value of t=21 in the exponential equation
f(21)=57
=57
=57*36315.5
=2069983.5
Hence the population on 21st march is 2069983.5.
Learn more about equation at brainly.com/question/2972832
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Answer:
<h2>
cos 30°= 0.866</h2>
Step-by-step explanation:
Step one:
Applying the SOH CAH TOA principle
assuming all dimensions are in cm
Step two:
Given data
opposite= 1 cm
hypotenuse= 2 cm
<h3>we can now solve for θ</h3>
Sin(θ)= opp/hyp
Sin(θ)= 1/2
Sin(θ)= 0.5
θ= sin-1 0.5
θ= 30°
hence from tables cos 30°= 0.866