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Dafna11 [192]
2 years ago
15

A pair of equations is shown below: y = 3x − 5 y = 6x − 8 Part A: Explain how you will solve the pair of equations by substituti

on or elimination. Show all the steps and write the solution. (5 points) Part B: If the two equations are graphed, at what point will the lines representing the two equations intersect? Explain your answer. (5 points) Source StylesNormal
Mathematics
2 answers:
Scrat [10]2 years ago
7 0

Answer:

Intersect/Solution at (1, -2)  

step by step

Equation 1: y = 3x - 5

Equation 2: y = 6x - 8

Step 1 Mutliply each side of equations one by -2

New Equation 1: -2y = -6x + 10

New Equation 2: y = 6x -8

Add the Equations: -y = +2

Multiply each side by -1 and you'll get that y = -2

Plug in -2 to either equation: -2 = 3x - 5

add 2 to each side 0 = 3x -3

add 3 to each side 3x = 3

divide by 3 and you'll get that x = 1

Step-by-step explanation:

kirill [66]2 years ago
3 0

Answer:

Intersect/Solution at (1, -2)

Step-by-step explanation:

Equation 1: y = 3x - 5

Equation 2: y = 6x - 8

Step 1 Mutliply each side of equations one by -2

New Equation 1: -2y = -6x + 10

New Equation 2: y = 6x -8

Add the Equations: -y = +2

Multiply each side by -1 and you'll get that y = -2

Plug in -2 to either equation: -2 = 3x - 5

add 2 to each side 0 = 3x -3

add 3 to each side 3x = 3

divide by 3 and you'll get that x = 1

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Answer:

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hope this helped

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3 years ago
Solve Sine inverse x +sine inverse 2x = π/3 <br> Please solve it faster..
LuckyWell [14K]
Arcsin x + arcsin 2x = π/3

arcsin 2x =  π/3 - arcsin x

sin[arcsin 2x] = sin[π/3 - arcsin x] (remember the left side is like sin(a-b)

2x = sinπ/3 cos(arcsin x)-cosπ/3 sin(arc sinx)

2x = √3/2 . cos(arcsin x) - (1/2)x)

but cos(arcsin x) = √(1-x²)===>2x = √3/2 .√(1-x²)  - (1/2)x)

Reduce to same denominator:

(4x) = √3 .√(1-x²)  - (x)===>5x = √3 .√(1-x²)

Square both sides==> 25x²=3(1-x²)

28 x² = 3 & x² = 3/28 &  x =√(3/28)



3 0
2 years ago
A tree that grows 3 feet every 5 years is growing at a rate of ___ feet per year.
Anni [7]
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8 0
3 years ago
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For what real values of does the quadratic 12x^2+k*x+27=0 have nonreal roots
icang [17]

Step-by-step explanation:

Discriminant : k² - 4(12)(27) < 0

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2 years ago
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bezimeni [28]

Answer:

scale factor = \frac{1}{3}

Step-by-step explanation:

the scale factor is the ratio of corrresponding sides. image to original.

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7 0
2 years ago
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