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yan [13]
3 years ago
13

How large of a container would be needed to hold 800 g of water?

Mathematics
2 answers:
kirill [66]3 years ago
8 0
Since water has a density of 1 gram per cubic centimetre, then the container would need to be 800 cubic centimetres. if this container were a perfect cube,<span>then the length of the side of the container would be equal to the cube-root of </span>
Gwar [14]3 years ago
6 0
The container would<span> need to be </span>800<span> milliliters or </span>800<span> cubic centimeters, because there is one gram of mass in one cubic centimeter of </span>water<span>.</span>
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Fishermen fishing for spiny lobster are allowed to keep only lobsters with a carapace length of 3.25 inches or longer. (Than car
ser-zykov [4K]

Answer:

16%

Step-by-step explanation:

First we start by solving for the z score

We have the following information

x = 3.25

Standard deviation = sd = 2.25

Mean = 5.50

Z = (x - mean)/sd

z = 3.25 - 5.50/2 25

z = -1.00

If we look this up in the standard normal distribution table,

P(z<-1.00) = 0.1587

Which when approximated gives us

16%

Therefore approximately 16% of lobsters will have to be returned back to the sea.

4 0
3 years ago
Please guys I am begging you to help me! This was due yesterday and I need help! SO please help!
jeka57 [31]

Answer:

  • Q3. 12 units
  • Q4. 6.33 units
  • Q5. 66.19°

Step-by-step explanation:

Q3

DE and DF are legs and EF is hypotenuse

  • DE = √EF² - DF²
  • DE = √13² - 5² = √169 - 25 = √ 144 = 12
  • DE = 12 units

Q4

PR is opposite side of angle Q and RQ is adjacent side

  • tan 54 = PR/RQ
  • tan 54 = PR / 4.6
  • PR = 4.6tan 54
  • PR = 6.33 units

Q5

As previous question, using tan as BC is opposite and AC is adjacent leg of angle A

  • tan A = 6.8/3
  • tan A = 2.266
  • A = arctan (2.266)
  • A = 66.19°
8 0
3 years ago
PLEASE HELP I HATE THIS SM I WANNA KMSS
dedylja [7]

Answer:

you want to flip the original coordinates and make them both negative so (x,y) would become (-y,-x) so in your problem here Q' would be (0,-7), R' would be (-5,-8), S' would be (-10,-7) and T' would be (-5,-2). Hope that helped :>

Step-by-step explanation:

6 0
3 years ago
F has 10 more marbles than I. Both boys have 15 marbles combined. How many marbles does each boy have?
olganol [36]

Answer:

F has 10 marbles and I has 5 marbles.

Step-by-step explanation:

First, I subtracted 10 from 15 since F has 10  more marbles than I. When I subtracted I got 5.

Hope this helps!!!!

4 0
3 years ago
What is fifty two thousand, fifty two in standard form
solniwko [45]
Fifty two thousand fifty two is equal to 52,052.
6 0
3 years ago
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