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yan [13]
3 years ago
13

How large of a container would be needed to hold 800 g of water?

Mathematics
2 answers:
kirill [66]3 years ago
8 0
Since water has a density of 1 gram per cubic centimetre, then the container would need to be 800 cubic centimetres. if this container were a perfect cube,<span>then the length of the side of the container would be equal to the cube-root of </span>
Gwar [14]3 years ago
6 0
The container would<span> need to be </span>800<span> milliliters or </span>800<span> cubic centimeters, because there is one gram of mass in one cubic centimeter of </span>water<span>.</span>
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the length of a rectangle is 4 more than 3 times the width. If the perimeter of the rectangle is 18.4cm, what is the area of the
antoniya [11.8K]

Answer:

A = 10.27cm²

Step-by-step explanation:

Let's represent the width as x,

therefore since the length is 4 more than 3 times the width, it can be represent as 3x + 4,   Perimeter = 18.4cm

Perimeter of a rectangle = 2(L + B)

18.4= 2(3x+4+x)\\18.4= 6x+8+2x\\18.4-8=6x+2x\\10.4=8x\\x=\frac{10.4}{8}\\x=1.3

width = 1.3cm

Length = 3x + 4 = 3*1.3 + 4 = 7.9cm

Area of a rectangle = length x width

A = 7.9 * 1.3 = 10.27cm²

6 0
3 years ago
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mrs_skeptik [129]
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Dominik [7]

Answer:

7.06 x 10^(-7) ft 3

Step-by-step explanation:

We have the formula to calculate the volume of an octagonal Pyraamid as following:

<em>+) Volume of octagonal pyramid = 1/3 * Area of the base * Height</em>

As given, the base of the pyramid is an octagon with area equal to 15mm2

=> Area of the base = 15 mm2

The height of the pyramid is the length of the line segment which is perpendicular to the base - which is the red line.

=> Height = 4mm

So we have:

<em>Volume of octagonal pyramid = 1/3 * Area of the base * Height</em>

<em>= 1/3 * 15 * 4 = 20 mm3</em>

<em />

As: 1 mm3 = 3.53 x 10^(-8) ft 3

=> 20 mm3 = 7.06x10^(-7) ft 3

So the volume of the pyramid is :  7.06 x 10^(-7) ft 3

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Sara will have a 3,360 interest fee.

Step-by-step explanation:

4% of 1,400 is 56. 56 X 60 = 3,360

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