Let

be the point on the ground to with the 18 foot guy is anchored and

the point on the ground to with the 21 foot guy is anchored.
We can conclude that the <span>the two wires at the points where they are anchored are
21 feet apart. Check the procedures in the picture attached.</span>
Answer:
(x + 5)^2 = (5 - 3)^2
Step-by-step explanation:
Given the equation;
x^2 + 10x + 22 = 13
We have;
x^2 + 10x = 13 - 22
x^2 + 10x = -9
Adding half of 10 to both sides and completing the square as usual, we have;
(x + 5)^2 = 5^2 + (-9)
(x + 5)^2 = (5 - 3)^2
This is probably the answer I’m not 100% sure
Answer:
9.000000001
Step-by-step explanation:
If the hypotenuse is 15, the ladder, facing the right angle, and the opposite is 12 we need to use SOH to find the angle.
sin of angle is opposite / hypotenuse
sin of angle is 12 / 15
12/15 = 0.8
sin^-1 of 0.8 = 53.13010235
Angle is that
Then we do this again but a different equation
cos of angle is adjacent (x which we are looking for) / hypotenuse
cos of 53.13... is x / 15
(15 x cos of 53.13... )is x
So 15 x cos of 53.13... is 9.000000001 feet away.