What is the Answer Please Help

Can somebody plz help answer the number 10’s questions using the diagram from the bottom left side (only if u know how to do thi

Lana71 [14]

Answer:

10a: △ABC is an Equilateral triangle with all acute angles.

10b: △BCD is A scalene triangle with all acute angles.

10c: △BDE is An Isosceles triangle with one obtuse angle.

Step-by-step explanation:

10) Looking at the diagram at the bottom left;

- △ABC has 3 equal internal angles and as such, it means it will have 3 equal angles.

Thus, we can classify it as; Equilateral triangle with all acute angles.

- △BCD has 3 unequal angles. Thus, it's 3 sides are not equal. Also all the angles are less than 90°.

We can classify it as;

A scalene triangle with all acute angles

- △BDE has 2 equal angles and one angle greater than 90°. This means it has 2 equal sides.

Thus, we can classify it as;

- An Isosceles triangle with one obtuse angle.

8 0

2 years ago

How to integrate ∫㏑x/χ from 1 to e

Natali [406]

$\int_1^e\dfrac{\ln x}{x}dx,~\text{if}~u=\ln x\to x=e^u\to dx=e^udu\\\\\text{So, finding the new limits:}\begin{cases}x=1\to u=\ln1\to u=0\\x=e\to u=\ln e\to u=1\end{cases}\\\\
\int_1^e\dfrac{\ln x}{x}dx=\int_0^1\dfrac{u}{e^u}e^udu=\int_0^1u\,du=\left[\dfrac{u^2}{2}\right]_0^1=\dfrac{1^2}{2}-\dfrac{0^2}{2}=\dfrac{1}{2}\\\\
\boxed{\int_1^e\dfrac{\ln x}{x}dx=\dfrac{1}{2}}$

6 0

2 years ago

If the Math Olympiad Club consists of 11 students, how many different teams of 3 students can be formed for competitions?

vivado [14]

Answer:

165 different teams of 3 students can be formed for competitions

Step-by-step explanation:

Combinations of m elements taken from n in n (m≥n) are called all possible groupings that can be made with the m elements so that:

Not all items fit
No matter the order
Elements are not repeated

That is, a combination is an arrangement of elements where the place or position they occupy within the arrangement does not matter. In a combination it is interesting to form groups and their content.

To calculate the number of combinations, the following expression is applied:

$C=\frac{m!}{n!*(m-n)!}$

It indicates the combinations of m objects taken from among n objects, where the term "n!" is called "factorial of n" and is the multiplication of all the numbers that go from "n" to 1.

In this case:

n: 3
m: 11

Replacing:

$C=\frac{11!}{3!*(11-3)!}$

Solving:

$C=\frac{11!}{3!*8!}$

being:

3!=3*2*1=6
8!=8*7*6*5*4*3*2*1=40,320
11!=39,916,800

So:

$C=\frac{39,916,800}{6*40,320}$

C= 165

165 different teams of 3 students can be formed for competitions

3 0

2 years ago

If an exercise routine requires 24 crunches for every 16 squats, how many squats would need to be done for every 78 crunches? Gr

Angelina_Jolie [31]

Answer:

The correct answer is 52 squats.

Step-by-step explanation:

An exercise routine requires 24 crunches for every 16 squats.

Therefore the routine would require 1 crunch for every $\frac{16}{24}$ squats.

And by the use of unitary method, the routine would require 78 crunches for every $\frac{16}{24}$ × 78 squats = 52 squats.

Thus for every 78 crunches attempted, the exercise routine would requires 52 squats to be done.

3 0

3 years ago

CONSIDER THE EQUATION WHAT IS THE VALUE OF X THAT MAKE THIS EQUATION TRUE

RoseWind [281]

Answer:

The answer is x=1.

Step-by-step explanation:

7 0

2 years ago