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2 years ago

Need help asap with b and c!!! plz help for a cookie :)

Mathematics

1 answer:

Debora [2.8K]2 years ago

4 0

You can think of this question like the photo attached above.

Hi!

I think for b, the answer would be:

You can construct an angle that is one fourth the measure of angle JKL, by dividing angle either angle MKL or JKM in half.
This is because one-fourth is also equal to one quarter (1/4). If you split angle JKL into 4 equal angles, you would have an angle that is one-fourth the measure (original angle) of angle JKL.

I think for c, the answer would be:

You can construct a 15 degree angle from a given 60 degree angle, by dividing the 60 degree angle into 4 equal angles.
This would work, because each of the 4 angles would be 15 degrees.

Hope this helps! Best of luck!

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How to determine if a function is even or odd calculus?

aalyn [17]

A function $f(x)$ is even if $f(-x)=f(x)$ , and is odd if $f(-x)=-f(x)$ .

Example:

$f(x)=x^2$ is even, since $f(-x)=(-x)^2=x^2=f(x)$ .

$g(x)=x^3-x$ is odd, since $g(-x)=(-x)^3-(-x)=-x^3+x=-(x^3-x)=-g(x)$ .

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2 years ago

Im new to this app can someone help me please and thank u so much

GaryK [48]

Answer:

$3\frac{1}{4}$

Step-by-step explanation:

we have to divide the given distance by 3.

Then we will be able to find the distance between markers.

Given distance is

$9\frac{3}{4} \\=\frac{36+3}{4}\\ =\frac{39}{4}$

Since, there are three markers,

So, we have to divide this distance by 3

So, the distance between markers is-

$\frac{\frac{39}{4}} {3} \\=\frac{39}{4} * \frac{1}{3} \\=\frac{13}{4}$

So, the distance between marker is

$\frac{13}{4}$

Now, we have to convert this into mixed number.

Then, the distance is-

$\frac{13}{4}\\ =3\frac{1}{4}$

4 0

2 years ago

Find the value of x.

Cerrena [4.2K]

$x^2 + (x + 3)^2 = (\sqrt{117})^2$

$x^2 + x^2 + 6x + 9 = 117$

$2x^2 + 6x -108 = 0$

$x^2 + 3x - 54 = 0$

$(x + 9)(x - 6) = 0$

$x + 9 = 0 ~~or~~ x - 6 = 0$

$x = -9 ~~ or~~ x = 6$

Since the side of a triangle cannot have a negative length, we discard the solution x = -9.

Answer: x = 6

3 0

2 years ago

Read 2 more answers

PLS HELP ITS A MAJOR GRADE AND DUE TOMORROW

Alexus [3.1K]

Answer:

*See below*

Step-by-step explanation:

Identify and Explain Error

The method shown is using fractions to compare costs. This strategy does not work due to the fact that they have not factored in the $55 he pays for the car before hand. Also, 150 divided by 0.5 does not equal 30, it equals 300 so, even if he did not pay $55 beforehand, the equation is still incorrect.

Correct Work/Solution

$55 to rent

$0.50 per mile

Let's start by removing $55 from $150 to see how many dollars is left over for gas.

150 - 55 = 95

Then, divide 95 by 0.5

95 ÷ 0.5 = 190

He can drive at least 190 miles.

Share Strategy

Since he starts off paying $55 dollars out of $150, we need to subtract $55 by $150 to see how much cash he has left over for mileage. $150 minus $55 equals $95 so, he has $95 left over for mileage. $95 will then be divided by $0.50 to find out how many miles he can drive. We are dividing by $0.50 because that's the cost per mile. $95 divided by $0.50 equals 190 so he can drive at least 190 miles.

Note:

Hope this helps :)

Have a great day!

7 0

2 years ago

What is the surface area using integrals of these two lines. Y=10-x^2 and Y=x^2+2 from the bounds x=2 and x=-2.

Lelu [443]

Check the picture below.

$\bf \displaystyle\int\limits_{-2}^{2}~[\stackrel{\textit{above function}}{(10-x^2)}~~-~~\stackrel{\textit{below function}}{(x^2+2)}]dx\implies \int\limits_{-2}^{2}~(10-x^2-x^2-2)dx \\\\\\ \displaystyle\int\limits_{-2}^{2}~(8-2x^2)dx\implies \left. 8x\cfrac{}{} \right]_{-2}^{2}-\left. \cfrac{2x^3}{3} \right]_{-2}^{2} \\\\\\ ([16]-[-16])~~-~~\left( \left[ \cfrac{16}{3} \right]-\left[ -\cfrac{16}{3} \right]\right)\implies (32)~~-~~\left( \cfrac{32}{3} \right) \\\\\\ \cfrac{64}{3}\implies 21\frac{1}{3}$

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3 years ago