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3 years ago

Need help asap with b and c!!! plz help for a cookie :)

Mathematics

1 answer:

Debora [2.8K]3 years ago

4 0

You can think of this question like the photo attached above.

Hi!

I think for b, the answer would be:

You can construct an angle that is one fourth the measure of angle JKL, by dividing angle either angle MKL or JKM in half.
This is because one-fourth is also equal to one quarter (1/4). If you split angle JKL into 4 equal angles, you would have an angle that is one-fourth the measure (original angle) of angle JKL.

I think for c, the answer would be:

You can construct a 15 degree angle from a given 60 degree angle, by dividing the 60 degree angle into 4 equal angles.
This would work, because each of the 4 angles would be 15 degrees.

Hope this helps! Best of luck!

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What is 69 over 24 as a terminating decimal

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2.875 is 69/24 as a terminating decimal

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Write the sum of the numbers as the product of their GCF and another sum.

8090 [49]

Answer:

See explanation

Step-by-step explanation:

1. Find the GCF of 40 and 44:

$40=\underline{2\cdot 2}\cdot 2\cdot 5\\ \\44=\underline{2\cdot 2}\cdot 2\cdot 11\\ \\GCF(40,44)=2\cdot 2=4$

So,

$40+44=4\cdot 10+4\cdot 11=4\cdot (10+11)$

2. Find the GCF of 13 and 52:

$13=\underline{13}\\ \\52=2\cdot 2\cdot \underline{13}\\ \\GCF(13,52)=13$

So,

$13+52=13\cdot 1+13\cdot 4=13\cdot (1+4)$

3. Find the GCF of 15 and 81:

$15=\underline{3}\cdot 5\\ \\81=\underline{3}\cdot 3\cdot 3\cdot 3\\ \\GCF(15,81)=3$

So,

$15+81=3\cdot 5+3\cdot 27=3\cdot (5+27)$

4. Find the GCF of 64 and 28:

$64=\underline{2\cdot 2}\cdot 2\cdot 2\cdot 2\cdot 2\\ \\28=\underline{2\cdot 2}\cdot 7\\ \\GCF(64,28)=2\cdot 2=4$

So,

$64+28=4\cdot 16+4\cdot 7=4\cdot (16+7)$

6 0

3 years ago

Sugar was traditionally produced and sold as sugarloaves, which are cones of sugar wrapped in paper. Find the total surface area

Zolol [24]

Answer:

A = 326,73 cm²

Step-by-step explanation:

The area of a circular cone is area of the base (A₁ ) plus area lateral ( area of a circular sector of radius the slant height )

Then we proceed to calculate the area of the base A₁

diameter of circular base is 8 cm then the radius is 4 cm and the area is:

A₁ = π*r² = 3,14* (4)²

A₁ = 3,1416*16 = 50,2656 cm²

Now Lateral area of the cone (A₂) is equal to the area of a circular sector with radius the slant height. We will calculate it, taken into account that this circular sector is part of a circle of radius the slant height.

Between the area of circular sector with radius the slant height and the area of the circle with the same radius there is a linear relation. That is we can calculate area of a circular sector by rule of three as follows:

The length of the circular sector is the length of the circle of the base of the cone, that is:

L = 2*π*(4)

L = 2*3,1416*4

L = 25,1328 cm

Then we have a circular sector of length 25,1328 cm

The area of the circle of radius 22 cm is:

A(c) = π*(22)² ⇒ A(c) = 1520,5344 cm²

And the length of this circle is:

L(c) = 2*π*(22) ⇒ 138,2304 cm

Then we apply a rule of three

For a length of 138,2304 cm ⇒⇒⇒ (area) 1520,5344 cm²

Then for a length of 25,1328 cm ⇒⇒⇒(area) A₂ (??)

Therefore:

A₂ = (25,1328)*1520,5344)/ 138,2304

A₂ = 276,4608 cm²

Then total area of the cone is:

A = A₁ + A₂

A = 50,2656 +276,4608

A = 326,7264 cm²

Round answer A = 326,73 cm²

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Answer:

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Step-by-step explanation:

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