Question

Find the value of x in the isosceles triangle shown below​

Answer 1

Answer:

D

Step-by-step explanation:

The segment x is a perpendicular bisector and divides the triangle into 2 right triangles.

Using Pythagoras' identity in either of the 2 right triangles, then

x² + 4² = 8²

x² + 16 = 64 ( subtract 16 from both sides )

x² = 48 ( take the square root of both sides )

x = $\sqrt{48}$ → D

Answer 2

Answer:

x²+4² =8²

x²+16 =64

x² =64-16.

x² =48

x. =√48

answer is option D