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katen-ka-za [31]
3 years ago
9

I need some help with this one

Mathematics
1 answer:
k0ka [10]3 years ago
8 0
I believe the answer is 3
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Perpendicular lines are lines that ___ ?
konstantin123 [22]

Answer:

Perpendicular lines are lines that intersect at a right (90 degrees) angle.

Step-by-step explanation:

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Which of the answer choices could be the one missing data item for the following set, if the mode is 12?
crimeas [40]

Answer:

D

Step-by-step explanation:

first of all, what is mode: it is the highest occuring number in a set of numbers.

now since 12 is supposed to be the mean and it occurs twice but 9 also occurs twice so for 12 to be the mode, we must add one more 12.

therefore the answer is 12

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a 120 watt light bulb uses about 0.1 kilowatt of electricity per hour. if electricity costs 0.20 per kilowatt hour, how much doe
Allushta [10]
A 120 watt light-bulb is a 0.120 kilowatt light bulb.

In one hour, it uses 0.120 kilowatt-hour of energy.

If electrical energy costs $0.20 per kilowatt hour, then that light bulb costs

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                            (0.120 x $0.20 / hour)  =  

                                       $0.024 / hour  =  <span>2.4¢  per hour </span>
5 0
3 years ago
Please what is the interquartile range ?
AleksAgata [21]

Answer:

3.

Step-by-step explanation:

15 - 12 = 3.

The ends of the box are the lower and upper quartiles.

The difference  upper - lower = the interquartile range.

6 0
2 years ago
find the volume of the solid formed by revolving the region bounded by the graphs of y = 4x - x^2 and f(x) = x^2 from [0,2] abou
Neko [114]

Answer:

v =  \frac{32\pi}{3}

or

v=33.52

Step-by-step explanation:

Given

f(x) = 4x - x^2

g(x) = x^2

[a,b] = [0,2]

Required

The volume of the solid formed

Rotating about the x-axis.

Using the washer method to calculate the volume, we have:

\int dv = \int\limit^b_a \pi(f(x)^2 - g(x)^2) dx

Integrate

v = \int\limit^b_a \pi(f(x)^2 - g(x)^2)\ dx

v = \pi \int\limit^b_a (f(x)^2 - g(x)^2)\ dx

Substitute values for a, b, f(x) and g(x)

v = \pi \int\limit^2_0 ((4x - x^2)^2 - (x^2)^2)\ dx

Evaluate the exponents

v = \pi \int\limit^2_0 (16x^2 - 4x^3 - 4x^3 + x^4 - x^4)\ dx

Simplify like terms

v = \pi \int\limit^2_0 (16x^2 - 8x^3 )\ dx

Factor out 8

v = 8\pi \int\limit^2_0 (2x^2 - x^3 )\ dx

Integrate

v = 8\pi [ \frac{2x^{2+1}}{2+1} - \frac{x^{3+1}}{3+1} ]|\limit^2_0

v = 8\pi [ \frac{2x^{3}}{3} - \frac{x^{4}}{4} ]|\limit^2_0

Substitute 2 and 0 for x, respectively

v = 8\pi ([ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ] - [ \frac{2*0^{3}}{3} - \frac{0^{4}}{4} ])

v = 8\pi ([ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ] - [ 0 - 0])

v = 8\pi [ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ]

v = 8\pi [ \frac{16}{3} - \frac{16}{4} ]

Take LCM

v = 8\pi [ \frac{16*4- 16 * 3}{12}]

v = 8\pi [ \frac{64- 48}{12}]

v = 8\pi * \frac{16}{12}

Simplify

v = 8\pi * \frac{4}{3}

v =  \frac{32\pi}{3}

or

v=\frac{32}{3} * \frac{22}{7}

v=\frac{32*22}{3*7}

v=\frac{704}{21}

v=33.52

8 0
3 years ago
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