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Answer:
The functions given are:
f(x) = x²
g(x) = f(-4x-3) + 1
First, find f(-4x-3):
f(x) = x²
f(-4x-3) = (-4x-3)²
Find g(x):
g(x) = f(-4x-3) + 1
g(x) = (-4x-3)² + 1
g(x) = (-1)² (4x+3)² + 1
g(x) = (4x+3)² + 1
First take
y = (x)²
Compress the graph along x axis by multiplying x with 4
y = (4x)²
Shift the graph left by 0.75 units, by adding 3 to x term.
y = (4x+3)²
Shift the graph up by 1 unit by adding 1 to the total terms.
y = (4x+3)² +1
The answer is 
.
Explanation:
In order to subtract the fractions, we must make them like fractions. To do this, the denominators must be the same by multiplying (only). Since the first fraction is
, 3 can be multiplied by 2 to get 6, which is the other fraction, we can multiply it. Whatever you do to the denominator you must do to the numerator. Now multiply 2 by the numerator (10) to get 
. Now we can subtract the fractions and 
to get 13/6. Since this fraction is not in mixed fraction form yet, we must do that first. goes into 13 twice, so the whole number is 2 and there is still 1 left, making the fraction 
. Therefore, the difference is 2 .
Explanation:
In order to subtract the fractions, we must make them like fractions. To do this, the denominators must be the same by multiplying (only). Since the first fraction is