In the function m=4n, n is the...

in a diagram of a landscape plan the scale is 1 cm 10 ft in the diagram the trees are 5.2 cm apart. how far apart should the act

vazorg [7]

The scale of the drawing is 1 cm to 10 feet. This means, every 1 cm of the drawing represents 10 feet in actual.

The trees are 5.2 cm apart in the drawing. So according to the given scale, they will be 5.2 x 10 = 52 feet apart in actual.

So actual bushes be planted at a distance of 52 feet.

5 0

2 years ago

Graph y=-6(3)^x please do the table and the graph 20 POINTS!

Margarita [4]

Answer:

Explanation to the answer below... (Answers in the Explanation)

Step-by-step explanation:

We Know that our rule is y = $y = -6(3)^{x}$ , which means we can use this rule to find y from x. Since we don't know what X, is, we have to assume numbers like 1, to 7. And there is no space to write on the graph, I'll put a virtual copy of a graph.

1st Point,

$y = -6(3)^{x}\\y = -6(3)^{1}\\y = -6(3)\\y = -18\\x = 1, y = -18$

2nd, point

$y = -6(3)^x\\ y = -6(3)^2\\y = -6(9)\\y = -54\\x = 2, y = -54$

3rd Point

$y = -6(3)^x\\y = -6(3)^3\\y = -6(27)\\y = -162\\x = 3, y = -162$

4th Point

$y = -6(3)^4\\y = -6(81)\\y = -486\\x = 4, y = -486\\$

5th Point

$y = -6(3)^5\\y = -6(243)\\y = -1458\\\x = 5, y = -1458$

6th Point

$y = -6(3)^x\\y = -6(3)^6\\y = -6(729)\\y = -4,374\\x = 6, y = -4,374\\$

7th Point (Last Point)

$y = -6(3)^x\\y = -6(3)^7\\y = -6(2,187)\\y. = -13,122\\x = 7, y = -13,122$

Let's now plot them on the Graph, the values are so big, the graph might look a little odd.

Always remember that we can continue the points infinitely, and there is no stop, The Graph is attached below...

4 0

2 years ago

Okay I know I suck at math and I really don't understand math that well so can you help me on this??? Thank you!

Alja [10]

W - width
l - length
p - perimeter

The perimeter is 72 cm (p=72).
The length is twice the width (l=2w).
The formula for perimeter is 2w+2l=P.

$p=72 \\
l=2w \\ \\
2w+2l=p \\
2w+2 \cdot 2w=72 \\
2w+4w=72 \\
6w=72 \\
w=12 \\ \\
l=2w=2 \cdot 12 =24$

Check the answer:
$2 \cdot 12 + 2 \cdot 24 \stackrel{?}{=} 72 \\
24+48 \stackrel{?}{=} 72 \\
72 \stackrel{?}{=} 72 \\ \hbox{true}$

The length of the photo is 24 cm, the width of the photo is 12 cm.

8 0

3 years ago

The Thompson family borrowed $120,000

kolezko [41]

Answer:

27,600

Step-by-step explanation:

6 0

3 years ago

Persons taking a 30-hour review course to prepare for a standardized exam average a score of 620 on that exam. Persons taking a

Alina [70]

Given:

30-hour review course average a score of 620 on that exam.

70-hour review course average a score of 749.

To find:

The linear equation which fits this data, and use this equation to predict an average score for persons taking a 57-hour review course.

Solution:

Let x be the number of hours of review course and y be the average score on that exam.

30-hour review course average a score of 620 on that exam. So, the linear function passes through the point (30,620).

70-hour review course average a score of 749. So, the linear function passes through the point (70,749).

The linear function passes through the points (30,620) and (70,749). So, the linear equation is:

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$

$y-620=\dfrac{749-620}{70-30}(x-30)$

$y-620=\dfrac{129}{40}(x-30)$

$y-620=\dfrac{129}{40}(x)-\dfrac{129}{40}(30)$

$y-620=\dfrac{129}{40}(x)-\dfrac{387}{4}$

Adding 620 on both sides, we get

$y=\dfrac{129}{40}x-\dfrac{387}{4}+620$

$y=\dfrac{129}{40}x+\dfrac{2480-387}{4}$

$y=\dfrac{129}{40}x+\dfrac{2093}{4}$

We need to find the y-value for $x=57$ .

$y=\dfrac{129}{40}(57)+\dfrac{2093}{4}$

$y=183.825+523.25$

$y=707.075$

$y\approx 707.1$

Therefore, the required linear equation for the given situation is $y=\dfrac{129}{40}x+\dfrac{2093}{4}$ and the average score for persons taking a 57-hour review course is 707.1.

4 0

2 years ago