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sergij07 [2.7K]
3 years ago
10

4 + 3(4 - 2)^2 - 3(3 - 2)^3

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
7 0
PEMDAS

4+3(4-2)^2 - 3(3-2)^3
4+3(2)^2 - 3(1)^3
4+3(4) - 3(1)
4+12-3
16-3
13

The answer is 13
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I need help please and thank you
ExtremeBDS [4]

Answer:

D=340

Step-by-step explanation:

360-180/9

360-20

340

4 0
3 years ago
Please answer correctly !!!!!!!! Will mark brianliest !!!!!!!!!!!
nexus9112 [7]

Answer:

x=6

Step-by-step explanation:

h(x) = -( x-2)^2 +16

We want when h(x) = 0

0 = -( x-2)^2 +16

Subtract 16 from each side

-16  = -( x-2)^2 +16-16

-16 = -( x-2)^2

Divide by -1

16= ( x-2)^2

Take the square root of each side

±sqrt(16) = sqrt(( x-2)^2 )

±4 = x-2

Add 2 to each sdie

2 ±4 = x-2+2

2+4 = x     2-4 =x

6 =x           -2 =x

since time cannot be negative

x=6

4 0
3 years ago
Pleaseee helppp with thissss asapppp
Natasha2012 [34]

As we know that the standard equation of circle is {\bf{(x-h)^{2}+(y-k)^{2}=r^{2}}} , where <em>r</em> is the radius of circle and centre at <em>(h,k) </em>

Now , as the circle passes through <em>(2,9)</em> so it must satisfy the above equation after putting the values of <em>h</em> and <em>k</em> respectively

{:\implies \quad \sf \{2-(-1)\}^{2}+(9-5)^{2}=r^{2}}

{:\implies \quad \sf (3)^{2}+(4)^{2}=r^{2}}

{:\implies \quad \sf 9+16=r^{2}}

After raising ½ power to both sides , we will get <em>r = +5 , -5</em> , but as radius can never be -<em>ve</em> . So <em>r = +</em><em>5</em><em> </em>

Now , putting values in our standard equation ;

{:\implies \quad \sf \{x-(-1)\}^{2}+(y-5)^{2}=(5)^{2}}

{:\implies \quad \bf \therefore \quad \underline{\underline{(x+1)^{2}+(y-5)^{2}=25}}}

<em>This is the required equation of </em><em>Circle</em>

Refer to the attachment as well !

8 0
2 years ago
If f(x) = x over 2 + 8, what is f(x) when x = 10?
jeka57 [31]

Answer:

f(10) = 13

Step-by-step explanation:

f(x) = x/2 + 8

Let x = 10

f(10) = 10/2 +8

f(10) = 5+8

f(10) = 13

8 0
3 years ago
Please help me to solve all the questions would appreciate it if its with full working
Degger [83]

∠ KGH is equal to 77°. This is arrived at by using the knowledge of the total angles in Parallel Lines.

<h3>What are the total angles on a straight line?</h3>

According to the laws of lines and angles, the total number of angles that can exist on a straight line is 180°.

If ∠CED = 25° and ∠BFL = 78°, then: ∠KGH = 180-(25+78), which is equals 77°. This is because the total angles on a straight-line total 180°

<h3>What is ∠LKJ?</h3>

Recall that in angles in parallel lines:

  • Corresponding Angles are always congruent,  
  • Alternate Angles are always congruent, and
  • Interior According always sum up to 180°

Hence,

We can derive ∠LKJ because it is congruent with ∠BGJ.

To get ∠BGJ, we must get ∠LFH because both of them are interior angles and sum up to 180°.

To get ∠LFH, we must subtract ∠BFL from 180° because they are both angles on a straight line.

Hence ∠LFH = 180 - 78 = 102°

Recall that ∠LFH and ∠BGJ are interior angels. Hence

∠BGJ = 180 - 102 = 78°.

Since ∠BGJ is a corresponding ∠ with ∠LKJ, therefore

∠LKJ = 78°

<h3>What is ∠ALM?</h3>

∠ALM is ∠BFL because they are both corresponding angles and are therefore congruent.

<h3>What are the solutions to section B?</h3>

  1. Because ∠ACB and ∠BAC are equal, therefore sides AB and BC are equal in length. We can tell that  ∠ACB and ∠BAC are equal because the total angles in the triangle are equal to 180°

     2. The name given to the triangle mentioned above is Obtuse      

          Triangle. This is because one of the angles exceeds 90°.

Learn more about angles in parallel lines at:
brainly.com/question/24607467
#SPJ1

4 0
1 year ago
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