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Zielflug [23.3K]
3 years ago
6

Plz helppp I need help on this

Mathematics
2 answers:
a_sh-v [17]3 years ago
4 0

Answer:

36π in^2

Step-by-step explanation:

The formula for calculating area of a circle is π×r^2

since the radius is given as 6

π × 6^2 = 36π in^2

maksim [4K]3 years ago
3 0

Answer:

The answer is 3rd point, 36π in²

Step-by-step explanation:

Given that thr formula of area of circle is A = π×radius². Then you can substitute the following values into the formula:

radius = 6 in

A = π × 6²

= 36π in²

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Complete the patterns 3,400,000 34,000 blank 3.4 blank
almond37 [142]
340 and 0.034 because yo move two decimal points to the left
6 0
3 years ago
Read 2 more answers
a charitable organization in Lanberry is hosting a black tie benefit. Yesterday, the organization sold 55 regular tickets and 49
jenyasd209 [6]

Answer:

  • regular: $67
  • VIP: $122

Step-by-step explanation:

Let r and v represent the costs of a regular and VIP ticket, respectively. The two sales can be represented by ...

  55r +49v = 9663

  79r +84v = 15541

We can subtract 7 times the second equation from 12 times the first to eliminate the v terms.

  12(55r +49v) -7(79r +84v) = 12(9663) -7(15541)

  660r +588v -553r -588v = 115,956 -108,787 . . . . . eliminate parentheses

  107r = 7169 . . . . . . . simplify

  r = 67 . . . . . . . . . . . divide by 107

Using this value in the first equation, we have ...

  55(67) +49v = 9663

  v = 5978/49 . . . . . . . . . subtract 3685, divide by 49

  v = 122

A regular ticket costs $67; a VIP ticket costs $122.

_____

<em>Additional comment</em>

When using "elimination" to solve a system of equations, you're looking for coefficients of the same variable that are related by small factors. Preferably, one coefficient is the same as, or a small multiple of, the other. Here, 55 and 79 (the coefficients of x) are not related by an integer, or a couple of small integers. On the other hand, the y-coefficients 49 and 84 have a common factor of 7, and are in the ratio 7:12, a pair of small numbers. This is why we chose to eliminate the y-variable.

The x-variable could be eliminated using 55 and -79 as multipliers of the equations. This results in larger numbers, and more chance for error. (Errors tend to creep in when computing or copying large numbers.)

Of course, any of several machine methods could be used to solve these equations, including graphing and matrix-solving functions. Here, we tried to honor the requirement to solve by elimination.

7 0
2 years ago
Preston bought a drum set priced at 187.90. The sales tax was found by multiplying the price of the drum set by 0.08. What was t
kobusy [5.1K]

Answer:

202.90

Step-by-step explanation:

If 187.90 is the price before the sales tax, you will multiply it by the 0.08 tax which will give you 15.032. You take 15.032 and add it to 187.90 because that is the sales tax. And after you add it and round to the nearest cent you get 202.90

7 0
3 years ago
Consider the two lines l1:x=−2t,y=1+2t,z=3tl1:x=−2t,y=1+2t,z=3t and l2:x=−8+4s,y=0+5s,z=5+1sl2:x=−8+4s,y=0+5s,z=5+1s find the po
seraphim [82]

At the point of intersection, the coordinates are the same:

... (x, y, z) = (-2t, 1+2t, 3t) = (-8+4s, 5s, 5+s)

We only need two of the coordinates to solve for the values of s and t. Using the x- and y-coordinates, we have

... 4s + 2t = 8 . . . . . . x2 - x1 = 0, in standard form

... 5s -2t = 1 . . . . . . . y2 - y1 = 0, in standard form

Adding these equations gives 9s=9, so s=1. Substituting into either equation gives t=2.

Using the expression for l1 with t=2, the point of intersection is

... (-2·2, 1+2·2, 3·2) = (-4, 5, 6).

_____

We could have stopped after finding the value of s, because that defines the point. By finding the value of t, we can check the solution to make sure that l1 and l2 both give the same point for the respective values of s and t. (They do.)

8 0
3 years ago
Triangle ABC has vertices at A(2,3),B(-4,-3) and C(2,-3) find the coordinates of each point of concurrency.
dem82 [27]

Answer:

Circumcenter =(-1,0)

Orthocenter =(2,-3)

Step-by-step explanation:  

Given : Points A = (2,3), B = (-4,-3), C = (2,-3)  

Formula used :  

→Mid point of two points- (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

→Slope of two points - \frac{y_2-y_1}{x_2-x_1})

→Perpendicular of a line = \frac{-1}{slope of line})

Circumcenter- The point where the perpendicular bisectors of a triangle meets.

Orthocenter-The intersecting point for all the altitudes of the triangle.

To find out the circumcenter we have to solve any two bisector equations.

We solve for line AB and AC

So, mid point of AB =(\frac{2-4}{2},\frac{3-3}{2})=(-1,0)

Slope of AB =\frac{-3-3}{-4-2}=1

Slope of the bisector is the negative reciprocal of the given slope.  

So, the slope of the perpendicular bisector = -1  

Equation of AB with slope -1 and the coordinates (-1,0) is,  

(y – 0) = -1(x – (-1))  

y+x=-1………………(1)  

Similarly, for AC  

Mid point of AC = (\frac{2+2}{2},\frac{3-3}{2})=(2,0)

Slope of AC = \frac{-3-3}{2-2}=\frac{-6}{0}  

Slope of the bisector is the negative reciprocal of the given slope.  

So, the slope of the perpendicular bisector = 0  

Equation of AC with slope 0 and the coordinates (2,0) is,  

(y – 0) = 0(x – 2)  

y=0 ………………(2)  

By solving equation (1) and (2),  

put y=0 in equation (1)

y+x=-1

0+x=-1

⇒x=-1  

So the circumcenter(P)= (-1,0)

To find the orthocenter we solve the intersections of altitudes.

We solve for line AB and BC

So, mid point of AB =(\frac{2-4}{2},\frac{3-3}{2})=(-1,0)

Slope of AB =\frac{-3-3}{-4-2}=1

Slope of the bisector is the negative reciprocal of the given slope.  

So, the slope of CF = -1  

Equation of AB with slope -1 and the coordinates (-1,0) gives equation CF  

(y – 0) = -1(x – (-1))  

y+x=-1………………(3)  

Similarly, mid point of BC =(\frac{-4+2}{2},\frac{-3-3}{2})=(-1,-3)

Slope of AB =\frac{-3+3}{-4-2}=0

Slope of the bisector is the negative reciprocal of the given slope.  

So, the slope of AD = 0

Equation of AB with slope 0 and the coordinates (-1,-3) gives equation AD

(y-(-3)) = 0(x – (-1))  

y+3=0

y=-3………………(4)  

Solve equation (3) and (4),

Put y=-3 in equation (3)

y+x=-1

-3+x=-1

x=2

Therefore, orthocenter(O)= (2,-3)


7 0
3 years ago
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