If 12 divided by 36 is 3 then multiply 15 by 3 to get 45 as the answer
Find the gradient
m = y2-y1 / x2-x1
m = 4-(-2) / 3-(-3)
m = 6 / 6
m = 1
Insert the values of one of the points into y=mx+c to find c (choosing point (3,4)):
y = mx + c
4 = 1(3) + c
c = 4 - 3
c = 1
Therefore, the equation is:
y = x + 1
H(t)=-16t^2+25t
The maximum height occurs at the vertex of the quadratic.
The vertex of a quadratic is always at:
(x,y)=(-b/(2a), (4ac-b^2)/(4a))
So the maximum height is:
(4ac-b^2)/(4a), and in our equation a=-16, b=25, and c=0 so
hmax=(0-25^2)/(-64)
hmax=-625/-64
hmax=9.765625
hmax≈9.8 ft (to nearest tenth of a foot)
then the angle formed would be equal to 180 degree
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