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kondor19780726 [428]
3 years ago
11

Can somone help me with this please

Mathematics
2 answers:
yaroslaw [1]3 years ago
8 0

Answer:

undefined

0

Step-by-step explanation:

We can use the slope formula

m = (y2-y1)/(x2-x1)

m = (-7 -5)/(-6 - -6)

   = (-7-5)/(-6+6)

   -12 /0

undefined

m = (y2-y1)/(x2-x1)

m = (-3 - -3)/(7 - -8)

    = (-3+3)/(7+8)

    = 0/15

   = 0

Ivenika [448]3 years ago
7 0

Slope Formula: (y2 - y1) / (x2 - x1)

#1.

Point 1 = (-6,5)

Point 2 = (-6,-7)

Slope = (-7 - 5) / (-6 - -6) = -12 / 0 = undefined

#2.

Point 1 = (-8,-3)

Point 2 = (7,-3)

Slope = (-3 - - 3) / (7 - - 8) = 0 / 15 = 0 slope

Hope this helps!

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3. The length of a living room is 12 feet and its width is 10.5 feet. The length of the room is being
Liono4ka [1.6K]

Since you're adding x feet to the length which is 12 feet:

New area: (12+x)10.5

5 0
3 years ago
Compare -0.3 and -1/3
zaharov [31]
The answer is -0.1 I believe
4 0
3 years ago
A study was conducted to investigate the effectiveness of hypnotism in reducing pain. An SRS of 8 subjects was randomly selected
chubhunter [2.5K]

Answer:

e. No, the p-value is greater than 0.01, so there is insufficient evidence at the 0.01 level to conclude that pain levels are lower after hypnotism.

Step-by-step explanation:

Hello!

The study's objective is to test if hypnotism reduces pain.

A sample of n=8 subjects was taken and the pain level was recorded in each subject before and after being hypnotized.

The variable of interest was determined by calculating the difference of pain level after - before hypnosis. This is a paired sample test and the variable can be determined as:

Xd: Difference between pain level felt after hypnosis and pain level felt before hypnosis of a subject.

The sample average and standard deviation obtained were:

Xd= -3

Sd= 3

And the variable is presumed to be approximately normal.

An approximately normal distribution is enough to conduct a paired sample t-test.

If the claim is that hypnosis reduces pain, then the average pain level after hypnosis should be less than the average pain level before hypnosis, then the average difference is expected to be negative, symbolically: μd < 0

The test will be one-tailed and so will be the p-value.

Remember: The p-value is defined as the probability corresponding to the calculated statistic if possible under the null hypothesis (i.e. the probability of obtaining a value as extreme as the value of the statistic under the null hypothesis).

So first step is to calculate the value of the statistic under the null hypothesis and then you can calculate the p-value.

H₀: μd ≥ 0

H₁: μd < 0

t_{H_0}= \frac{X_d-Mu_{d}}{\frac{S_d}{n} }= \frac{-0-0}{\frac{3}{\sqrt{8} } } = -2.828= -2.83

The DF of the t-test are n-1= 7

Then you can calculate the p-value as:

P(t₇≤-2.83)= 0.0127

The level of the test is α: 0.01

The decision rule is:

If p-value ≤ α, reject the null hypothesis.

If p-value > α, do not reject the null hypothesis.

The p-value > α the decision is to not reject the null hypothesis.

Correct option: e. No, the p-value is greater than 0.01, so there is insufficient evidence at the 0.01 level to conclude that pain levels are lower after hypnotism.

I hope this helps!

5 0
3 years ago
Does anyone know how to do this
bezimeni [28]
You can turn 5 into 10/2 and add to x/2
then you need to use simple algebra to left the x alone in the equation so you need to multiply both sides by 2 so you get
2y=10+x
then you need to subtract both sides a 10 so
2y-10=x
now change the x to f'(x) and y to x so:
f'(x)=2x-10
7 0
1 year ago
PLEASE HELP. I WILL MARK BRAINLIEAST!!
emmainna [20.7K]
There’s technically two answers, you could put Angles 3 and 6, or Angles 7 and 2
3 0
3 years ago
Read 2 more answers
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