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2 years ago

A measurement that closely agrees with accepted values

Mathematics

1 answer:

bixtya [17]2 years ago

3 0

A measurement that closely agrees with an accepted value is best described as a numerical

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X<br>81** *34*=246<br><img src="https://tex.z-dn.net/?f=81x%20%2B%201%20%2B%203%7B4x%20%7D%20%3D%20246" id="TexFormula1" title="

anzhelika [568]

Answer:

$x=\frac{1}{4}$

Step-by-step explanation:

$81^{x+1}+3^{4x}=246$

$81=3^4$

Rewrite equation: $3^{4\left(x+1\right)}+3^{4x}=246$

$3^{4\left(x+1\right)}=3^{4x}\times 3^4$

$3^{4x}\times 3^4+3^{4x}=246$

Factor out $3^{4x}$ :

$3^{4x}\left(3^4+1\right)=246$

Divide both sides by $(3^4+1)$ :

$\frac{3^{4x}\left(3^4+1\right)}{3^4+1}=\frac{246}{3^4+1}$

$3^{4x}=\frac{246}{3^4+1}$

$3^{4x}=\frac{246}{82}$

$3^{4x}=3$

Anything to the power of 1 is itself. Hence,

$4x=1\\$

$x=\frac{1}{4}$

3 0

3 years ago

A hungry Emperor penguin was swimming 21 feet below sea level. It swam up 9 feet to eat a fish. What is the position of the peng

MatroZZZ [7]

Answer:

Step-by-step explanation:

21 feet below is written as -21

9 feet up is written as +9

So we have -21 + 9 = -12 or 12 feet below sea level

6 0

2 years ago

Read 2 more answers

The Taylor family went on vacation. They traveled 412 miles on Monday. At the end of the day Tuesday, the average speed of the c

mixer [17]

Answer:

d = 56x + 412

Step-by-step explanation:

To find the total number of miles traveled on Monday and Tuesday, use a linear equation to write the function.

y = mx+b where m is the speed or rate of change and b is the starting point.

The starting point on Tuesday is 412 miles. This is b.

The number of miles traveled on Tuesday is found by calculating 56 miles times the number of hours traveled. This is the slope or m.

So the equation is d = 56h + 412.

7 0

2 years ago

What is the mean of 20, 37, 43, 54, 83, 102, 117, 160, 208?

Alekssandra [29.7K]

Answer is 91.56 You add all the numbers up and divide by 9(There are 9 numbers in the sequence).

6 0

3 years ago

Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains liters of a dye solution with a

Alja [10]

Answer:

t = 460.52 min

Step-by-step explanation:

Here is the complete question

Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains 200 liters of a dye solution with a concentration of 1 g/liter. To prepare for the next experiment, the tank is to be rinsed with fresh water flowing in at a rate of 2 liters/min, the well-stirred solution flowing out at the same rate.Find the time that will elapse before the concentration of dye in the tank reaches 1% of its original value.

Solution

Let Q(t) represent the amount of dye at any time t. Q' represent the net rate of change of amount of dye in the tank. Q' = inflow - outflow.

inflow = 0 (since the incoming water contains no dye)

outflow = concentration × rate of water inflow

Concentration = Quantity/volume = Q/200

outflow = concentration × rate of water inflow = Q/200 g/liter × 2 liters/min = Q/100 g/min.

So, Q' = inflow - outflow = 0 - Q/100

Q' = -Q/100 This is our differential equation. We solve it as follows

Q'/Q = -1/100

∫Q'/Q = ∫-1/100

㏑Q = -t/100 + c

$Q(t) = e^{(-t/100 + c)} = e^{(-t/100)}e^{c} = Ae^{(-t/100)}\\Q(t) = Ae^{(-t/100)}$

when t = 0, Q = 200 L × 1 g/L = 200 g

$Q(0) = 200 = Ae^{(-0/100)} = Ae^{(0)} = A\\A = 200.\\So, Q(t) = 200e^{(-t/100)}$

We are to find t when Q = 1% of its original value. 1% of 200 g = 0.01 × 200 = 2

$2 = 200e^{(-t/100)}\\\frac{2}{200} = e^{(-t/100)}$

㏑0.01 = -t/100

t = -100㏑0.01

t = 460.52 min

6 0

3 years ago