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worty [1.4K]
3 years ago
9

Two-fifths if one less than a number is less than three-fifths of one mira than than number. What numbers are in the solution se

t of this problem
A. X < -5
B. X > -5
C. X > -1
D. X < -1
Mathematics
1 answer:
Sliva [168]3 years ago
5 0
A is the correct answer
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Help please. I don’t understand.
monitta
Multiply 270 × 7/100, which equals to 18.9, and then subtract 270 - 18.9, which gives you 251.1.
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3 years ago
F(d)=3d–7<br><br>f(9v+5) =<br><br>PLEASE HELP DUE TODAY
Alecsey [184]

Answer: I believe the correct answer is

9fv+5f

Step-by-step explanation: I had sum help but i did what i did and im pretty sure i dd a good job.

6 0
4 years ago
Y4+5y2+9 factorise please help me​
Veronika [31]

\displaystyle\ y^4 +5y^2+9=(y^2+3)^2-y^2=(y^2-y+3)(y^2+y+3)

7 0
3 years ago
Read 2 more answers
a band of 45 ewoks crash-landed in the forest last night. this sounds like a small problem, but the population will grow at the
kogti [31]

Given Information:

Starting population = P₀ = 45

rate of growth = 22%

Required Information:

Population every five years from this year to the year 2050 = ?

Answer:

Year \: 2020 = P(0) = 45e^{0} = 45\\\\Year \: 2025 = P(5) = 45e^{0.22*5} = 135\\\\Year \: 2030 = P(10) = 45e^{0.22*10} = 406\\\\Year \: 2035 = P(15) = 45e^{0.22*15} = 1,220\\\\Year \: 2040 = P(20) = 45e^{0.22*20} = 3,665\\\\Year \: 2045 = P(25) = 45e^{0.22*25} = 11,011\\\\Year \: 2050 = P(30) = 45e^{0.22*30} = 33,079\\\\

Step-by-step explanation:

The population growth can be modeled as an exponential function,

P(t) = P_0e^{rt}

Where P₀ is the starting population, r is the rate of growth of the population and t is the time in years.

We are given that starting population of 45 and growth rate of 22%

P(t) = 45e^{0.22t}

Assuming that the starting year is 2020,

Year \: 2020 = P(0) = 45e^{0} = 45\\\\Year \: 2025 = P(5) = 45e^{0.22*5} = 135\\\\Year \: 2030 = P(10) = 45e^{0.22*10} = 406\\\\Year \: 2035 = P(15) = 45e^{0.22*15} = 1,220\\\\Year \: 2040 = P(20) = 45e^{0.22*20} = 3,665\\\\Year \: 2045 = P(25) = 45e^{0.22*25} = 11,011\\\\Year \: 2050 = P(30) = 45e^{0.22*30} = 33,079\\\\

Therefore, the starting population of ewoks was 45 in 2020 and increased to 33,079 by 2050 in a time span of 30 years.

8 0
3 years ago
Find the sum.<br>(w - 2.4) + (1 - 0.5w)​
vodka [1.7K]

The sum of the given expression { (w - 2.4) + (1 - 0.5w)​ } is 0.5w - 1.4.

<h3>What is the sum of the given expression?</h3>

Given the expression in the question;

(w - 2.4) + (1 - 0.5w)​

Remove the parenthesis

w - 2.4 + 1 - 0.5w

Collect like terms and simplify

w - 2.4 + 1 - 0.5w

w  - 0.5w - 2.4 + 1

1w  - 0.5w - 2.4 + 1

0.5w - 1.4

Therefore, the sum of the given expression { (w - 2.4) + (1 - 0.5w)​ } is 0.5w - 1.4.

Learn more algebra Problems here; brainly.com/question/723406

#SPJ1

8 0
2 years ago
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