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dybincka [34]
3 years ago
14

I can't figure this one out....Find ALL polar coordinates of point P = (6, 31°). The explanations I've found thus far don't seem

to be correct.

Mathematics
1 answer:
arsen [322]3 years ago
8 0

Check the picture below.

so, as I see it, we can simply move from the point P, 360° counter-clockwise, the green one, and we'll be landing on a positive angle on the 1st Quadrant, the angle of 360° + 30° = 390°.

we can also move 360° clockwise, the red one, from P, so we'll be landing at -360° + 30 = -330°, also on the 1st Quadrant, but a negative counterpart.

now, if we move by jumps of 360° on either direction, we'll be landing coterminal with P all the time, so if we use simply multiply 360° by "n", some integer, then that angle added or subtracted from 30°, will be coterminal with P.

( 6 ,  30°±360n°)   where n ∈ ℤ.

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W = width

L * W = 60 \\
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L = \frac{32-2W}{2}\\
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d = 16^{2} - 4*1*60 =  256 - 240 = 16 \\\\
W1 = \frac{-16+\sqrt{16}}{-2} =  \frac{-12}{-2} = 6\\
W2 = \frac{-16-\sqrt{16}}{-2} =  \frac{-20}{-2} = 10\\

L1 = 10\\
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so

{L,W} = {6,10} or {10,6}

but L > W  so

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