Assuming that point s is the vertex of the angle and that line sq is between angle psr. We can get the correct measurement of angle psq by subtracting 99 degrees with the measurement of the angle made by qsr. Hope this helps. Have a nice day.
In order to prove the triangle is a right angled triangle we need to prove that the slope of the lines CA and BC and AB have any negative reciprocals.Lets find the slopes .
AB=(-1,3), (1,2) slope of AB = 2-3/1-(-1)= -1/2 slope of AB is -1/2
BC = (1,2), (-3,1) slope of BC is 1-2/-3-1= -1/-4 slope of BC is 1/4
Slope of CA =(-3,1)(-1,3) slope of 3-1/-1-(-3)=-2/-2=1
Since the slopes do not have any negative reciprocals so the triangle is not a right angled triangle
Answer:
Step-by-step explanation:x
+
3
y
=
−
27
27 in³
the volume of a cube = (length of side )³ = 3³ = 27 in³
(f×g)(-1) is -14.
Step-by-step explanation:
- Step 1: Calculate (f×g)(x) by using the formula (f×g)(x) = f(x) × g(x)
⇒ (f×g)(x) = (x + 3)(4x - 3)
⇒ (f×g)(x) = 4x² - 3x + 12x - 9
⇒ (f×g)(x) = 4x² + 9x - 9
- Step 2: Find (f×g)(-1) by substituting -1 in the place of x
⇒ (f×g)(-1) = 4(-1)² + 9(-1) - 9
⇒ (f×g)(-1) = 4 - 9 - 9 =-14
