The sequence is arithmetic as it goes down 3 every time
Arithmetic nth term formula is an=a1+d(n-1)
an=7-3(n-1)
an=7-3n+3
an=-3n+10
To find the 100th term substitute n for 100
a100=-3(100)+10
a100=-300+10
a100=-290
The 100th term is -290
9 - 6 + 4 × 13
First, simplify 4 × 13 to get 52. / Your problem should look like: 9 - 6 + 52
Second, simplify. Subtract 9 - 6 then add 52 onto that. / Your problem should look like: 55
Answer: 55
2x = 5 + 3
2x = 8
x = 8/2
x=4
Answer:
a) D(t) = ![\[20*\sqrt{5} * t\]](https://tex.z-dn.net/?f=%5C%5B20%2A%5Csqrt%7B5%7D%20%2A%20t%5C%5D)
b) 178.885 miles
Step-by-step explanation:
Ship A travels north at the rate of 20 mph.
Ship B travels east at the rate of 40 mph.
After t hours, Ship A is at a distance of 20t miles from the origin.
Similarly, Ship B is at a distance of 40t miles from the origin.
(a) Distance D(t) = ![\[\sqrt{(20t)^{2}+(40t)^{2}}\]](https://tex.z-dn.net/?f=%5C%5B%5Csqrt%7B%2820t%29%5E%7B2%7D%2B%2840t%29%5E%7B2%7D%7D%5C%5D)
= ![\[\sqrt{400*t^{2}+1600 * (t)^{2}}\]](https://tex.z-dn.net/?f=%5C%5B%5Csqrt%7B400%2At%5E%7B2%7D%2B1600%20%2A%20%28t%29%5E%7B2%7D%7D%5C%5D)
= ![\[\sqrt{2000*t^{2}}\]](https://tex.z-dn.net/?f=%5C%5B%5Csqrt%7B2000%2At%5E%7B2%7D%7D%5C%5D)
=
(b) Distance between the two ships when t = 4,
= ![\[20*\sqrt{5} * 4\]](https://tex.z-dn.net/?f=%5C%5B20%2A%5Csqrt%7B5%7D%20%2A%204%5C%5D)
= ![\[80*\sqrt{5} \]](https://tex.z-dn.net/?f=%5C%5B80%2A%5Csqrt%7B5%7D%20%5C%5D)
miles
= 80 * 2.236
= 178.885 miles
Answer:
standard form
Step-by-step explanation:
The equation of a line in standard form is
Ax + By = C ( A is a positive integer and B, C are integers )
