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3 years ago

Which value of a in the exponential function below would cause the function to stretch?

Mathematics

2 answers:

lesya692 [45]3 years ago

8 0

Answer:

$51251552 | \sqrt[ { {).5644}^{2} }^{25} ]{051} |$

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Darina [25.2K]3 years ago

4 0

Answer:

1.5

Step-by-step explanation:

Took the test already.

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Convert 1 4/16 into a percent.

lorasvet [3.4K]

Answer:

it is 25 percent

Step-by-step explanation:

8 0

2 years ago

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The population of a local species of dragonfly can be found using an infinite geometric series where a1 = 42 and the common rati

Scilla [17]

Since this is the formula for the infinite geometric series with
a1 = 42
r = 3/4

Solution will be

sum = 42 / 1-3/4
sum = 42 / 0.25
sum = 168

Therefore, the total is 168

8 0

3 years ago

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Solve the inequality. X-5 < 16 A. X> 21 B. x<21 C. x< 11 D. x> 11

larisa [96]

Answer:

x < 21

Step-by-step explanation:

x - 5 < 16

x < 21 Add 5 to both sides

4 0

3 years ago

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Which shows where the function is increasing?

V125BC [204]

Answer:

In zone A and zone E.

Step-by-step explanation:

See the attached graph to this question.

The graph clearly shows that the function is increasing in the portion which is denoted by A and E.

In the A zone, the graph moves from minima towards local maxima and in the E zone, the graph moves from a local minima towards maxima.

In both the zones, the value of f(x) increases as the value of x increases. Therefore, the function is increasing in A and E zone. (Answer)

4 0

3 years ago

Let ????C be the positively oriented square with vertices (0,0)(0,0), (2,0)(2,0), (2,2)(2,2), (0,2)(0,2). Use Green's Theorem to

bonufazy [111]

Answer:

-48

Step-by-step explanation:

Lets call L(x,y) = 10y²x, M(x,y) = 4x²y. Green's Theorem stays that the line integral over C can be calculed by computing the double integral over the inner square of Mx - Ly. In other words

$\int\limits_C {L(x,y)} \, dx + M(x,y) \, dy = \int\limits_0^2\int\limits_0^2 (M_x - L_y ) \, dx \, dy$

Where Mx and Ly are the partial derivates of M and L with respect to the x variable and the y variable respectively. In other words, Mx is obtained from M by derivating over the variable x treating y as constant, and Ly is obtaining derivating L over y by treateing x as constant. Hence,

M(x,y) = 4x²y
Mx(x,y) = 8xy
L(x,y) = 10y²x
Ly(x,y) = 20xy
Mx - Ly = -12xy

Therefore, the line integral can be computed as follows

$\int\limits_C {10y^2x} \, dx + {4x^2y} \,dy = \int\limits_0^2\int\limits_0^2 -12xy \, dx \, dy$

Using the linearity of the integral and Barrow's Theorem we have

$\int\limits_0^2\int\limits_0^2 -12xy \, dx \, dy = -12 \int\limits_0^2\int\limits_0^2 xy \, dx \, dy = -12 \int\limits_0^2\frac{x^2y}{2} |_{x = 0}^{x=2} \, dy = -12 \int\limits_0^22y \, dy \\= -24 ( \frac{y^2}{2} |_0^2) = -24*2 = -48$

As a result, the value of the double integral is -48-

3 0

3 years ago