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Paraphin [41]
3 years ago
13

Which value of a in the exponential function below would cause the function to stretch?

Mathematics
2 answers:
lesya692 [45]3 years ago
8 0

Answer:

51251552 | \sqrt[ { {).5644}^{2} }^{25} ]{051} |

hhkhgguiffhkjgilkgfgkhff

Darina [25.2K]3 years ago
4 0

Answer:

1.5

Step-by-step explanation:

Took the test already.

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Convert 1 4/16 into a percent.
lorasvet [3.4K]

Answer:

it is 25 percent

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
The population of a local species of dragonfly can be found using an infinite geometric series where a1 = 42 and the common rati
Scilla [17]


Since this is the formula for the infinite geometric series with
a1 = 42
r = 3/4

Solution will be

sum = 42 / 1-3/4
sum = 42 / 0.25
sum = 168

Therefore, the total is 168






8 0
3 years ago
Read 2 more answers
Solve the inequality.<br> X-5 &lt; 16<br> A. X&gt; 21<br> B. x&lt;21<br> C. x&lt; 11<br> D. x&gt; 11
larisa [96]

Answer:

x < 21

Step-by-step explanation:

x - 5 < 16

x < 21           Add 5 to both sides

4 0
3 years ago
Read 2 more answers
Which shows where the function is increasing?
V125BC [204]

Answer:

In zone A and zone E.

Step-by-step explanation:

See the attached graph to this question.

The graph clearly shows that the function is increasing in the portion which is denoted by A and E.

In the A zone, the graph moves from minima towards local maxima and in the E zone, the graph moves from a local minima towards maxima.

In both the zones, the value of f(x) increases as the value of x increases. Therefore, the function is increasing in A and E zone. (Answer)

4 0
3 years ago
Let ????C be the positively oriented square with vertices (0,0)(0,0), (2,0)(2,0), (2,2)(2,2), (0,2)(0,2). Use Green's Theorem to
bonufazy [111]

Answer:

-48

Step-by-step explanation:

Lets call L(x,y) = 10y²x, M(x,y) = 4x²y. Green's Theorem stays that the line integral over C can be calculed by computing the double integral over the inner square  of Mx - Ly. In other words

\int\limits_C {L(x,y)} \, dx + M(x,y) \, dy =  \int\limits_0^2\int\limits_0^2 (M_x - L_y ) \, dx \, dy

Where Mx and Ly are the partial derivates of M and L with respect to the x variable and the y variable respectively. In other words, Mx is obtained from M by derivating over the variable x treating y as constant, and Ly is obtaining derivating L over y by treateing x as constant. Hence,

  • M(x,y) = 4x²y
  • Mx(x,y) = 8xy
  • L(x,y) = 10y²x
  • Ly(x,y) = 20xy
  • Mx - Ly = -12xy

Therefore, the line integral can be computed as follows

\int\limits_C {10y^2x} \, dx + {4x^2y} \,dy = \int\limits_0^2\int\limits_0^2 -12xy \, dx \, dy

Using the linearity of the integral and Barrow's Theorem we have

\int\limits_0^2\int\limits_0^2 -12xy \, dx \, dy = -12 \int\limits_0^2\int\limits_0^2 xy \, dx \, dy = -12 \int\limits_0^2\frac{x^2y}{2} |_{x = 0}^{x=2} \, dy = -12 \int\limits_0^22y \, dy \\= -24 ( \frac{y^2}{2} |_0^2) = -24*2 = -48

As a result, the value of the double integral is -48-

3 0
3 years ago
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