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4 years ago

Find the excluded value of the rational expression 2x + 6/4x - 8

2 answers:

5 0

2x + (6/(4x)) - 8 = 2x + 2(3/(2x)) - 8 => excluded value is 0
<span>(2x + 6)/(4x - 8) = [2(x+3)]/[4(x-2)] = (x+3)/[2(x-2)] => excluded value is 2</span>

frozen [14]4 years ago

3 0

Answer:

for connections

1.a

2.c

3.d

4.c

Step-by-step explanation:

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I'll assume the ODE is

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Solve the homogeneous ODE,

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has roots at $r=1$ and $r=2$ . Then the characteristic solution is

$y = C_1 e^x + C_2 e^{2x}$

For nonhomogeneous ODE (1),

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consider the ansatz particular solution

$y = axe^x \implies y' = a(x+1) e^x \implies y'' = a(x+2) e^x$

Substituting this into (1) gives

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For the nonhomogeneous ODE (2),

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take the ansatz

$y = bxe^{2x} \implies y' = b(2x+1) e^{2x} \implies y'' = b(4x+4) e^{2x}$

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2 years ago

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jok3333 [9.3K]

Answer:

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Step-by-step explanation:

$6x^{2} +1 = 487$ (Given)

-1 -1 (Getting "x" alone)

$6x^{2} = 486$ (Cont. Getting "x" alone)

÷6 ÷6 ↓

$x^{2} = 81$ ↓

$\sqrt{x} ^2 = \sqrt{81}$ (9 and -9 squared are both equal to 81)

↓ ↓ ↓

x = 9 x = -9 (Answer)

Hope this Helps! :)

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yaroslaw [1]

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