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3 years ago

Find the excluded value of the rational expression 2x + 6/4x - 8

2 answers:

5 0

2x + (6/(4x)) - 8 = 2x + 2(3/(2x)) - 8 => excluded value is 0
(2x + 6)/(4x - 8) = [2(x+3)]/[4(x-2)] = (x+3)/[2(x-2)] => excluded value is 2

frozen [14]3 years ago

3 0

Answer:

for connections

1.a

2.c

3.d

4.c

Step-by-step explanation:

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1){(-8,-10), (-2,0), (1,10), (4,0)} Domain= Range- Function?

adoni [48]

Answer:

domain(-8. -2. 1 4

range( -10 0 10 0

and the the given exp is function

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3 years ago

PLEASE HELP ILL GIVE BRAINLIESTTTT :)

Taya2010 [7]

Answer:

Yes, these triangles are congruent

∠E≅∠M

Step-by-step explanation:

Yes, these triangles are similar.

Proof:

Each side in LNM is $1\frac{2}{3}$ times longer than the sides in GFE

$30/18 = 1\frac{2}{3}$

$25/15=1\frac{2}{3}$

$20/12 = 1\frac{2}{3}$

According CPCTC (corresponding parts of congruent triangles are congruent), angle E is similar to angle M.

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2 years ago

A line that included the points (d,-4) and (-2,2) has a slope of -2. What is the value of d

Citrus2011 [14]

(2+4)/(-2-d) = -2

6 = -2(-2-d)
6 = 4 + 2d

2 = 2d

1 = d

3 0

3 years ago

Prove this trigonometric equation; - tan^2x + sec^2x = 1,

alekssr [168]

Hey there :)

- tan²x + sec²x = 1 or 1 + tan²x = sec²x

sin²x + cos²x = 1
Divide the whole by cos²x

$\frac{sin^2x}{cos^2x} + \frac{cos^2x}{cos^2x} = \frac{1}{cos^2x}$

$\frac{sinx}{cosx} = tanx$ so $\frac{sin^2x}{cos^2x} = tan^2x$
and
$\frac{1}{cosx} = secx$ so $\frac{1}{cos^2x} = sec^2x$

Therefore,
tan²x + 1 = sec²x
Take tan²x to the other side {You will have the same answer}

1 = - tan²x = sec²x or sec²x - tanx = 1

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3 years ago

Need help ASAP Will mark you brainlist

sattari [20]

Answer:

Step-by-step explanation:

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2 years ago