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Tema [17]
3 years ago
11

Given that

2 \sqrt{32} = {2}^{x} " alt="32 \sqrt{32} = {2}^{x} " align="absmiddle" class="latex-formula">
, find the value of x
​
Mathematics
1 answer:
Gelneren [198K]3 years ago
5 0

Answer:

x = 7.5 or 15/2

Step-by-step explanation:

2^{5} \cdot2^{5/2} = 2^{15/2}

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If 18 is 45% of value, what is that value
____ [38]
Percent  is parts out of 100 so
45%=45/100=9/20
'of' means multiply
18 =9/20 times something
multiply both sides by 20/9 to clear fraction
360/9=something
40=something

the value is 40
8 0
3 years ago
Read 2 more answers
Navy PilotsThe US Navy requires that fighter pilots have heights between 62 inches and78 inches.(a) Find the percentage of women
Zigmanuir [339]

The first part of the question is missing and it says;

Use these parameters: Men's heights are normally distributed with mean 68.6 in. and standard deviation 2.8 in. Women's heights are normally distributed with mean 63.7 in. and standard deviation 2.9 in.

Answer:

A) Percentage of women meeting the height requirement = 72.24%

B) Percentage of men meeting the height requirement = 0.875%

C) Corresponding women's height =67.42 inches while corresponding men's height = 72.19 inches

Step-by-step explanation:

From the question,

For men;

Mean μ = 68.6 in

Standard deviation σ = 2.8 in

For women;

Mean μ = 63.7 in

Standard deviation σ = 2.9 in

Now let's calculate the standardized scores;

The formula is z = (x - μ)/σ

A) For women;

Z = (62 - 63.7)/2.9 = - 0.59

Z = (78 - 63.7)/2.9 = 4.93

The original question cam be framed as;

P(62 < X < 78).

So thus, the probability of only women will take the form of;

P(-0.59 < Z < 4.93) = P(Z<4.93) - P(Z > - 0.59)

From the normal probability table attached, when we interpolate, we'll arrive at P(Z<4.93) = 0.9999996

And P(Z > - 0.59) = 0.277595

Thus;

P(Z<4.93) - P(Z > - 0.59) =0.9999996 - 0.277595 = 0.7224

So, percentage of women meeting the height requirement is 72.24%.

B) For men;

Z = (62 - 68.6)/2.8 = -2.36

Z = (78 - 68.6)/2.8 = 3.36

Thus, the probability of only men will take the form of;

P(-2.36 < Z < 3.36) = P(Z<3.36) - P(Z > - 2.36)

From the normal probability table attached, when we interpolate, we'll arrive at P(Z<3.36) = 0.99961

And P(Z > -2.36) = 0.99086

Thus;

P(Z<3.36) - P(Z > -2.36) 0.99961 - 0.99086 = 0.00875

So, percentage of women meeting the height requirement is 72.24%.

B)For women;

Z = (62 - 63.7)/2.9 = - 0.59

Z = (78 - 63.7)/2.9 = 4.93

The original question cam be framed as;

P(62 < X < 78).

So thus, the probability of only women will take the form of;

P(-0.59 < Z < 4.93) = P(Z<4.93) - P(Z > - 0.59)

From the normal probability table attached, when we interpolate, we'll arrive at P(Z<4.93) = 0.9999996

And P(Z > - 0.59) = 0.277595

Thus;

P(Z<4.93) - P(Z > - 0.59) =0.9999996 - 0.277595 = 0.00875

So, percentage of women meeting the height requirement is 0.875%

C) Since the height requirements are changed to exclude the tallest 10% of men and the shortest10% of women.

For women;

Let's find the z-value with a right-tail of 10%. From the second table i attached ;

invNorm(0.90) = 1.2816

Thus, the corresponding women's height:: x = (1.2816 x 2.9) + 63.7= 67.42 inches

For men;

We have seen that,

invNorm(0.90) = 1.2816

Thus ;

Thus, the corresponding men's height:: x = (1.2816 x 2.8) + 68.6 = 72.19 inches

7 0
3 years ago
Help plssssss<br>1. (x +3) 2<br>2. 6÷2(1+2)<br>3. 15-1(12÷4+1)<br><br><br><br>​
Lisa [10]
1. 2x+7
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3.11
I help u there aowonxpwkdowiwvbwicbwocbiwcb
5 0
2 years ago
Pls, look at picture for the question.
brilliants [131]
-6.8 is the answer.
8 0
2 years ago
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I need help with 2 questions about circumference. ITS ALMOST DUE 20 POINTS thank you
aksik [14]

Answer:

This is against the honor code sry :(

Step-by-step explanation:

"Students are never allowed to post questions directly from tests, quizzes, and assessments, or copy answers found on Brainly during tests, quizzes, and assessments."

3 0
3 years ago
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