Given that

2 \sqrt{32} = {2}^{x} " alt="32 \sqrt{32} = {2}^{x} " align="absmiddle" class="latex-formula">
, find the value of x

Mathematics

1 answer:

Gelneren [198K]3 years ago

5 0

Answer:

x = 7.5 or 15/2

Step-by-step explanation:

$2^{5} \cdot2^{5/2} = 2^{15/2}$

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