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sdas [7]
3 years ago
8

X + x2 - 5x -5 = 0 state the possible rational zeros and find all the zeros of the polynomial

Mathematics
1 answer:
Mariulka [41]3 years ago
8 0

Answer:

<em>The zeros of the polynomial are -1 and 5</em>

Step-by-step explanation:

<u>Quadratic Equation Solving</u>

The standard representation of a quadratic equation is:

ax^2+bx+c=0

where a,b, and c are constants.

Solving with the quadratic formula:

\displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

We have the following equation to solve:

x+x^2-5x-5=0

Before attempting to solve it, we must simplify the equation.

Collecting like terms and reordering:

x^2-4x-5=0

Here: a=1, b=-4, c=-5

The discriminant of this quadratic equation is:

d=b^2-4ac

d=(-4)^2-4(1)(-5)=16+20=36

Given d is positive, the equation has two roots, and since d is a perfect square, both roots are rational.

Applying the formula:

\displaystyle x=\frac{4\pm \sqrt{36}}{2(1)}

\displaystyle x=\frac{4\pm 6}{2}

Dividing by 2:

x=2\pm 3

Separating both roots:

x = 2 + 3 = 5

x = 2 - 3 = -1

The zeros of the polynomial are -1 and 5

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