Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
1 answer:
Well the area of a trapezoid is defined by the following formula:
A =
where b₁ and b₂ are the bases of the trapezoid and h is the height of the trapezoid.
Let's plug in what we know into this formula:
h = 7 the perpendicular distance between the two bases
b₁ = 15 the shorter parallel side
b₂ = 25 the longer parallel side made up of 4 + 15 + 6
so, A =
This is in square units of measure of course, so 140 in²
A =
Let's plug in what we know into this formula:
h = 7 the perpendicular distance between the two bases
b₁ = 15 the shorter parallel side
b₂ = 25 the longer parallel side made up of 4 + 15 + 6
so, A =
This is in square units of measure of course, so 140 in²
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Given:
Diameter of the hole = 30 cm
To find:
The area of the hole.
Solution:
The radius of a circle is always half of the diameter. It is given that the diameter of the hole is 30 cm. So, the radius of the hole is:
Area of a circle is:
Putting and
in the above formula, we get
Therefore, the area of the hold is 706.5 square cm.
Answer:
L(18, 20)
Step-by-step explanation:
In JL, K is the midpoint. The coordinates of J are (2, 2), and the
coordinates of K are (10, 11). What are the coordinates of L?
Solution:
If O(x, y) is the midpoint between two points A() and B(
). The equation to determine the location of O is given by:
Since JL is a line segment and K is the midpoint. Given the location of J as (2, 2) and K as (10, 11). Let () be the coordinate of L. Therefore:
Therefore L = (18, 20)