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3 years ago

9

2. Mrs. Robert’s class went to the zoo for a field trip. The bus driver drove 256 miles in 4 hours. What was the driver’s averag

e speed per hour

2 answers:

insens350 [35]3 years ago

5 0

Answer:

64

Step-by-step explanation:

ANTONII [103]3 years ago

5 0

256/4= 64
His average speed was 64 miles per hour

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The regular price of a baseball hat is $15.65. If Julio buys the baseball hat on sale for 20% off the regular price, how much ch

larisa [96]

Begin by multiplying $15.65 by 0.20 to find what 20% of the regular price is. This gives you 3.13, which in this situation means $3.13.
To find the price with discount subtract 15.65-3.13. This gives you $12.52.
To find out the change, subtract 20-12.52. This gives you $7.48.
So, he will receive $7.48 in change.
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2 years ago

Lexi needs 144 beads.A large box holds 100 beads.A medium box holds 10 beads.a small box holds 1 bead.lexi already had 1 large b

saveliy_v [14]

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3 years ago

Factor completely 2x2 9x 4. (2x 2)(x 2) (2x 1)(x 4) (2x 4)(x 1) (2x 2)(x 4).

lozanna [386]

Factors of the given expression are $(x+4), (2x+1)$

Given expression is

$2x^2 + 9x+4$

<h3>What is a factor?</h3>

A factor is a number that divides another number completely.

Let us split the middle term as:

$2x^2 + 8x + x+4\\\\2x(x+4)+1(x+4)\\\\(x+4) (2x+1)$

Therefore, factors of the given expression are $(x+4), (2x+1)$

To get more about factors visit:

brainly.com/question/9781037

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2 years ago

Evaluate 2b^3 where b = 3

densk [106]

Answer:

<em>Answer</em><em>=</em><em>5</em><em>4</em>

Step-by-step explanation:

Given:- b=3

2b³

Solution:-

2 x b³

2 x 3 x 3 x 3

6 x 9

54 (answer)

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Have a good day.

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2 years ago

Read 2 more answers

Suppose a simple random sample of size nequals36 is obtained from a population with mu equals 74 and sigma equals 6. (a) Descri

OlgaM077 [116]

Part a)

The simple random sample of size n=36 is obtained from a population with

$\mu = 74$

and

$\sigma = 6$

The sampling distribution of the sample means has a mean that is equal to mean of the population the sample has been drawn from.

Therefore the sampling distribution has a mean of

$\mu = 74$

The standard error of the means becomes the standard deviation of the sampling distribution.

$\sigma_ { \bar X } = \frac{ \sigma}{ \sqrt{n} } \\ \sigma_ { \bar X } = \frac{ 6}{ \sqrt{36} } = 1$

Part b) We want to find

$P(\bar X \:>\:75.9)$

We need to convert to z-score.

$P(\bar X \:>\:75.9) = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: 1.9) \\ = 0.0287$

Part c)

We want to find

$P(\bar X \: < \:71.95)$

We convert to z-score and use the normal distribution table to find the corresponding area.

$P(\bar X \: < \:71.95) = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: - 2.05) \\ = 0.0202$

Part d)

We want to find :

$P(73\:$

We convert to z-scores and again use the standard normal distribution table.

$P( \frac{73 - 74}{1} \:< \: z$

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3 years ago