Answer:
0.2941 = 29.41% probability that it was manufactured during the first shift.
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is

In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Defective
Event B: Manufactured during the first shift.
Probability of a defective item:
1% of 50%(first shift)
2% of 30%(second shift)
3% of 20%(third shift).
So

Probability of a defective item being produced on the first shift:
1% of 50%. So

What is the probability that it was manufactured during the first shift?

0.2941 = 29.41% probability that it was manufactured during the first shift.
Answer: False.
Step-by-step explanation:
48 is not a common factor of 4 and 6
4 and 6 only share 2 factor: 1 and 2
Factors in 4: 1, 2, 4
Factors in 6: 1, 2, 3, 6
Answer:
The expected value of one draw is the average value of these 10 slips of paper which is:
24 / 10 = 2.4
Step-by-step explanation:
We have a bag with 10 slips of paper in it. 8 slips of paper each has a 2 on them; 2 slips of paper each has a 4 on them.
The total value of all the slips when added together is:
= (8)(2) + (2)(4)
= 16 + 8 = 24
The expected value of one draw is the average value of these 10 slips of paper which is:
24 / 10 = 2.4 ....