Average speed for the entire trip, both ways, is
(Total distance) divided by (total time) .
We don't know the distance from his house to the gift store,
and we don't know how long it took him to get back.
We'll need to calculate these.
-- On the trip TO the store, it took him 50 minutes, at 6 mph.
-- 50 minutes is 5/6 of an hour.
-- Traveling at 6 mph for 5/6 of an hour, he covered 5 miles.
-- The gift store is 5 miles from his house.
-- The total trip both ways was 10 miles.
-- On the way BACK home from the store, he moved at 12 mph.
-- Going 5 miles at 12 mph, it takes (5/12 hour) = 25 minutes.
Now we have everything we need.
Distance:
Going: 5 miles
Returning: 5 miles
Total 10 miles
Time:
Going: 50 minutes
Returning: 25 minutes
Total: 75 minutes = 1.25 hours
Average speed for the whole trip =
(total distance) / (total time)
= (10 miles) / (1.25 hours)
= (10 / 1.25) miles/hours
= 8 miles per hour
Answer:
102,346 :)
Explanation:
Divide $409384 by 4 (409384/4) and you get your answer.
You would divide 8 3/4 by 50 to find out how many cups you would get for just one cupcake. So you would do 8 3/4 DIVIDED BY 50= 0.175 which means there will be 0.175 cups of sugar per cupcake.
The area of a circle is pi times the radius squared (A = π r²).
Answer:
km
Step-by-step explanation:
The submarine's path from its base forms a right triangle when its final position is "connected" to the base. We know that the right triangle has legs of 
km and 
km, and we need to find the length of its hypotenuse. To do so, we can use the Pythagorean Theorem, which states that in a right triangle, 
, where 
and 
are the lengths of the triangle's legs and 
is the length of the triangle's hypotenuse. In this case, we know what and are, and we need to solve for c, so after substituting the given values of and into to solve for c, we get:
(Substitute 
and 
into the equation)
(Evaluate the squares on the LHS)
(Simplify the LHS)
(Symmetric Property of Equality)
(Take the square root of both sides of the equation)
(Simplify)
is an extraneous solution because you can't have negative distance, if that makes sense, so therefore, the submarine is approximately km away from its base. Hope this helps!
