Answer:
This is a fourth-degree polynomial
X-intercepts are - 5, -5, 3, and -3
The Y-intercept is 225
Step-by-step explanation:
Since it's already in the factored form you can find the zeros by separating each binomial and solving for x
x
2
−
25
=
0
x
2
=
25
x
=
±
5
x
2
−
9
=
0
x
2
=
9
x
=
±
3
so
x
=
±
5
,
±
3
To find the y-intercept and the degree of the polynomial we need to convert the factored form into standard form
f
(
x
)
=
(
x
2
−
25
)
(
x
2
−
9
)
f
(
x
)
=
x
4
−
9
x
2
−
25
x
2
+
225
f
(
x
)
=
x
4
−
34
x
2
+
225
The degree of a polynomial is just the leading coefficients power which is 4 in this equation
In order to find the y-intercept we just need to allow
x
=
0
because that is when any equation will cross the y-axis
f
(
x
)
=
0
4
−
34
(
0
)
2
+
225
f
(
x
)
=
225
Force = mass x acceleration
Force = 1,100 kg x -1.2 m/s
Force = -1320 N
Independent variable - represents a quantity that is being manipulated
dependent variable- represents a quantity whose value depends on how the independent variable is manipulated.
For 5a+5b+5c=-20
A= -4 - b - c
B= -4 - a - c
C= -4 - a - b
———————————
4a+3b+3c=-6
A= -3/2 - 3b/4 - 3c/4
B= -2 - 4a/3 - c
C= -2 - 4a/3 - b
———————————
-4a+3b+3c=9
A= -9/4 + 3b/4 + 3c/4
B= 3 + 4a/3 - c
C= 3 + 4a/3 - b
Answer:
15% discount was offered with the family ticket option.
Step-by-step explanation:
We can see from our attachment that price for an adult day ticket is 55 and price for an child's ticket entrance is 45. While family ticket costs 170, which allows entrance for 2 adults and 2 children.
Let us find the cost of tickets without discount for 2 adults and two children.
![\text{ Price of tickets without discount}=2\times(55+45)](https://tex.z-dn.net/?f=%5Ctext%7B%20Price%20of%20tickets%20without%20discount%7D%3D2%5Ctimes%2855%2B45%29)
![\text{ Price of tickets without discount}=2\times(100)](https://tex.z-dn.net/?f=%5Ctext%7B%20Price%20of%20tickets%20without%20discount%7D%3D2%5Ctimes%28100%29)
![\text{ Price of tickets without discount}=200](https://tex.z-dn.net/?f=%5Ctext%7B%20Price%20of%20tickets%20without%20discount%7D%3D200)
The family of two 2 adults and 2 children will pay 200 without discount. Now let us find the percentage of discount offered with the family ticket option.
![\text{Percentage of discount offered with family ticket option}=\frac{(30)}{200}\times 100](https://tex.z-dn.net/?f=%5Ctext%7BPercentage%20of%20discount%20offered%20with%20family%20ticket%20option%7D%3D%5Cfrac%7B%2830%29%7D%7B200%7D%5Ctimes%20100)
![\text{Percentage of discount offered with family ticket option}=\frac{(30)}{2}=15](https://tex.z-dn.net/?f=%5Ctext%7BPercentage%20of%20discount%20offered%20with%20family%20ticket%20option%7D%3D%5Cfrac%7B%2830%29%7D%7B2%7D%3D15)
Therefore, the discount offered with the family ticket option is 15%.