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Dimas [21]
2 years ago
7

Quadrilateral WXYZ is dilated by a scale factor of į to form quadrilateral W'X'Y'Z'. What is the measure of side ZW? Z 28 Y" 42

42 W 28​
Mathematics
1 answer:
Brrunno [24]2 years ago
6 0

Answer:

See Explanation

Step-by-step explanation:

Given

<em>The given side lengths are not clear enough:</em>

<em>So, I will give a general explanation.</em>

<em />

From the question, we understand WXYZ is dilated to produce W'X'Y'Z

This implies that the sides of WYZY is multiplied by the scale factor (k) to give W'X'Y'Z'

i.e.

ZW *k =Z'W'

Divide both sides by k to get side length ZW

ZW = \frac{Z'W'}{k}

Assume that:

k = 4 and

Z'W' = 28

ZW = \frac{Z'W'}{k}

ZW = \frac{28}{4}

ZW = 7

<em>Apply these steps and you will get your answer</em>

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Answer:

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Read 2 more answers
3a
Jet001 [13]

Answer:

Option D is correct.

VS = 20 units.

Step-by-step explanation:

The complete question is contained in the attached image to this answer.

From the image attached and the additional information about the triangles, it is evident that that triangle VSW is similar to triangle QSR.

Hence, we can write the ratio as

(VS/QS) = (VW/QR)

VS = 2a

QS = 2 × VS = 2 × 2a = 4a

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Cross multiplying,

2a (3a + 6) = 4a (2a - 2)

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3a + 6 = 4a - 4

4a - 3a = 6 + 4

a = 10

VS = 2a = 20 units.

Hope this Helps!!!

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