23÷5=4 with a remainder of $3. each avocada was 4$.
Since p varies directly with l,
p = kl (1)
Also, since w varies directly with l,
w = ml
or, l = w/m
Substitute in (1), we get,
p = k (w/m)
= (k/m) w
So, the price varies directly with weight.
Given:
A rectangular greeting card uses a geometric design containing 4 congruent kites.
Consider the below figure attached with this question.
Length of card = 8 inches
Width of card = 4 inches
To find:
The area of one kite.
Solution:
The kites are connected to each other as shown below.
The length of a kite is:
inches
The width of a kite is:
inches
Area of a kite is:

Where,
are diagonals of the kite.
Length and width of a kite are 4 inches and 2 inches respectively. So, the diagonals of a kite are 4 inches and 2 inches.
Using the above formula, we get


The area of a kite is 4 sq. in.
Therefore, the correct option is A.