2x^2+4x-6=0
(2x^2+6x)(-2x-6)
2x(x+3) -2(x+3)
(2x-2)=0 (x+3)=0
x= 1 x=-3
The answer I got is d = 78
To start you need to get rid of the denominator so you add -4 by 8 to get 4 then multiply both sides by 4 to remove the denominator giving you -8= 5-y1. After that subtract 5 from both sides giving you -13= -y1, dividing by -1 you then get y1= 13
Answer:
this should be correct, im sorry im wrong.
Step-by-step explanation: