The equation of the line in point-slope form is given by:
Where,
(xo, yo): point that belongs to the line
m: slope of the line
The slope is given by:
Substituting values:
Rewriting:
Now we choose an ordered pair:
Substituting values we have:
We now rewrite the equation in its standard form:
Where,
b: cut with the y axis.
We have then:
Answer: point-slope form: or
standard form 
112 = 4.5p +40
112-40 =4.5p
72= 4.5p
72/4.5 = p
p= 16
he will.have to sell 16 pairs to hit is daily goal
Answer:
Radius = r = 7.5
Diameter = d = 15
Circumference = C = 15π
Step-by-step explanation:
We are given the image of a circle with a straight line passing through the center of the circle and touching its edges. Such a line is known as the diameter of the circle. From the image we can see the length of the diameter of the circle is d = 15 units.
Radius is define as half of the diameter. Since the diameter is 15 units, the radius of the given circle will be half of 15 which is r = 7.5 units.
Circumference of the circle = C = 2πr
Using the value of radius(r), we can write the circumference as:
C = 2π(7.5) = 15π
Answer:
66 cm²
Step-by-step explanation:
From the given figure, and the question statement we have;
BD = 11 cm, AE = 7 cm, CF = 5 cm
The given quadrilateral ABCD consists of two triangles; ΔABD and ΔBCD
The area of quadrilateral ABCD = The sum of the areas of ΔABD and ΔBCD
The base length of the two triangles equals segment BD = 11 cm
The height of triangle ΔABD = 7 cm
The area of a triangle = (1/2) × Base length × Height
∴ The area of triangle ΔABD = (1/2) × 11 cm × 7 cm = 38.5 cm²
Similarly;
The area of triangle ΔBCD = (1/2) × 11 cm × 5 cm = 27.5 cm²
∴ The area of quadrilateral ABCD = 38.5 cm² + 27.5 cm² = 66 cm²
The area of the given figure (quadrilateral ABCD) = 66 cm².
