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777dan777 [17]
3 years ago
10

(Urgent!) Explain how laundry detergent can be a product of biotechnology.

Biology
2 answers:
Zina [86]3 years ago
7 0

Answer:

Explanation:

Most biological laundry detergents contain lipase and protease enzymes, both of which are found in the body. Lipases break down fats and oils, while proteases work to break down protein chains. Their ability to break down these compounds makes them excellent for stain removal.

zysi [14]3 years ago
3 0

Answer:

Another important class of compounds produced by biotechnology is enzymes. One of the most significant commercial enzymes of this type is subtilisin, which is produced by a bacterium because many stains contain proteins, the manufacturers of laundry detergents include subtilisin in their product.

Explanation:

(please mark me brainliest if you can)

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3 years ago
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Considering the same population of cats as in Part A, what is the expected frequency of each genotype (TLTL, TLTS, TSTS ) based
zaharov [31]

Answer:

P = f(TLTL) = 0,16

H = f(TLTS) = 0,48

Q = f(TSTS) = 0,36

Explanation:

Hello!

The allele proportion of any locus defines the genetic constitution of a population. Its sum is 1 and its values ​​can vary between 0 (absent allele) and 1 (fixed allele).

The calculation of allelic frequencies of a population is made taking into account that homozygotes have two identical alleles and heterozygotes have two different alleles.

In this case, let's say:

f(TL) = p

f(TS) = q

p + q = 1

Considering the genotypes TLTL, TLTS, TSTS, and the allele frequencies:

TL= 0,4

TS= 0,6

Genotypic frequency is the relative proportion of genotypes in a population for the locus in question, that is, the number of times the genotype appears in a population.

P = f(TLTL)

H = f(TLTS)

Q = f(TSTS)

Also P + H + Q = 1

And using the equation for Hardy-Weinberg equilibrium, the genotypic frequencies of equilibrium are given by the development of the binomial:

p^{2} = f(TLTL)

2pq = f(TSTL)

q^{2} = f(TSTS)

So, if the population is in balance:

P = p^{2}

H = 2pq

Q = q^{2}

Replacing the given values of allele frecuencies in each equiation you can calculate the expected frequency of each genotype for the next generation as:

f(TLTL) = P = p^{2} = 0,4^{2} = 0,16

f(TLTS) = H = 2pq = 2*0,4*0,6 = 0,48

f(TSTS) = Q = q^{2} = 0,6^{2} = 0,36

I hope you have a SUPER day!

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your answer is

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