4 years ago

How do I solve 2cos(x)=2sin(2x)

1 answer:

4 0

2cosx=2sin2x. Sin2x is an identity for 2sinxcos. So 2[2sinxcosx] gives you 4sinxcosx. 2cosx=4sinxcosx. Divide 2cosx on both sides and gives you 2sinx=0 and divide again, sinx=0. Sinx is 0 at 0 and 360 degrees, or pi and 2pi. So thats what x would be. 0,360,pi,2pi.

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Help me with this question please, explain why u choose that answer and show ur steps

Setler [38]

Let’s condense the original expression and see if that’s one of the answers

-1/2(-3/2 x + 6x + 1) - 3x

First we distribute the -1/2

((-1/2)(-3/2 x) + (-1/2)(6x) + (-1/2)(1)) -3x

3/4x - 3x - 1/2 -3x

Combine like terms

(3/4 x - 3x - 3x) -1/2

-21/4 x - 1/2

We could make this a mixed number

-5 1/4 x - 1/2

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So the answer is D

7 0

3 years ago

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love history [14]

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Answer #3

5 0

4 years ago

At a local store, hot dogs come in packages of 8, and hot dog buns come in packages of 12. For her party, Arpitha purchased the

givi [52]

Answer:

Step-by-step explanation:

Find the factors of each until you get a match.

Hot dogs 8: 8, 16, 24

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4 0

3 years ago

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nevsk [136]

Step-by-step explanation:

9 = a7 + b

-2 = a9 + b

b = 9-7a and b = - 2-9a

9 - 7a = - 2-9a

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3 years ago

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Serjik [45]

Answer:

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Step-by-step explanation:

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3 years ago