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pshichka [43]
3 years ago
14

How do I solve 2cos(x)=2sin(2x)

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
4 0
2cosx=2sin2x. Sin2x is an identity for 2sinxcos. So 2[2sinxcosx] gives you 4sinxcosx. 2cosx=4sinxcosx. Divide 2cosx on both sides and gives you 2sinx=0 and divide again, sinx=0. Sinx is 0 at 0 and 360 degrees, or pi and 2pi. So thats what x would be. 0,360,pi,2pi.
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In each of the following pairs of numbers, how much larger is the first number than the second?
lapo4ka [179]

Answer: a. 154 is larger than 27 by 127.

b. 25 is larger than 12 by 13.

c.135 is larger than 127 by 8.

d.46 is larger than 24 by 22.


Step-by-step explanation:

Subtract second number from the first number.

a. 154 and 27

Difference=154-27=127

Hence, 154 is larger than 27 by 127.

b. 25 and 12

Difference=25-12=13

Hence, 25 is larger than 12 by 13.

c. 135 and 127

Difference=135-127=8

Hence, 135 is larger than 127 by 8.

d. 46 and 24

Difference=46-24=22

Hence, 46 is larger than 24 by 22.

4 0
3 years ago
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telo118 [61]

Look up what is mean and calculate it.

5 0
2 years ago
True or false? In a two column proof, the right column states your reasons
nikdorinn [45]

False. A two-column proof is also known as a "Statement-Reason Proof", with the statement column on the left and the reason column on the right.
8 0
3 years ago
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What are the correct steps for solving the following equation: 5x - 4= 21
AysviL [449]
1. Add 4 to both sides of the equation
2. Simplify
3. Divide both sides of the equation by 5
4. Simplify
5. x= 5
5 0
2 years ago
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A large jar contains a mixture of white and black beans. In a randomly chosen handful of 120 beans 40 were black. Create a 98% c
dusya [7]

Answer:

23%<x<43%

Step-by-step explanation:

The formula for calculating confidence interval is expressed;

Confidence Interval = p ± z√p(1-p)/n

n is the sample size

z is the z score at 98% confidence interval

n is the sample size = 120

z =  2.33

If in a randomly chosen handful of 120 beans 40 were black, then;

p = 40/120

p = 4/12

p = 0.33

CI = 0.33± 2.33√0.33(1-0.33)/120

CI = 0.33± [2.33√0.33(0.67)/120]

CI =  0.33± [2.33√0.2211/120]

CI = 0.33± [2.33(0.04292)]

CI = 0.33±0.100014

CI = (0.33-0.100014, 0.33+0.100014)

CI = (0.229, 0.430014)

CI = (22.9, 43.0014)

Hence 98% confidence interval for the proportion of black beans in the jar is 23%<x<43%.

6 0
2 years ago
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