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Len [333]
3 years ago
15

Find the price of 1 marker if 5 markers cost $15

Mathematics
2 answers:
Alex787 [66]3 years ago
5 0

Answer:

The price of 1 marker is $3

Step-by-step explanation:

15/5 = 3

Nostrana [21]3 years ago
4 0

Answer:

5 markers cost $6.55 :)

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A $525 speaker now sells for $393.75. Find the percent of change.
antiseptic1488 [7]

Answer: 25%

Step-by-step explanation:

595 - 393.75 = 131.25

131.25 (amount of change)/ 525 (original amount) x 100%

= 25%

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Allison has 4 1/2 cups of sugar. She used 2/3 of it to make cookies. How much sugar did Allison use for the cookies?
solmaris [256]
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Barron's reported that the average number of weeks an individual is unemployed is 17.5 weeks. Assume that for the population of
Olin [163]

Answer:

P(16.5

And using the normal standard table or excel we find the probability:

P(-1.768< Z< 1.768) = P(Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the avergae number of weeks an individual is unemployed of a population, and for this case we know the distribution for X is given by:

X \sim N(17.5,4)  

Where \mu=17.5 and \sigma=4

Since the distribution for X is normal then, the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu= 17.5, \frac{\sigma}{\sqrt{n}}= \frac{4}{\sqrt{50}}=0.566)

We select a sample of n =50 people. And we want to find the following probability

P(16.5

And using the normal standard table or excel we find the probability:

P(-1.768< Z< 1.768) = P(Z

4 0
3 years ago
Juno calculated the area of a square to be 4/9 square yard. Which shows the side length of the square?
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\bf \textit{area of a square}\\\\&#10;A=s^2~~&#10;\begin{cases}&#10;s=side's~length\\&#10;--------\\&#10;A=\frac{4}{9}&#10;\end{cases}\implies \cfrac{4}{9}=s^2&#10;\\\\\\&#10;\sqrt{\cfrac{4}{9}}=s\implies \cfrac{\sqrt{4}}{\sqrt{9}}=s\implies \cfrac{2}{3}=s
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3 years ago
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