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2 years ago

Will give you brainlyist pls help

Mathematics

1 answer:

Oliga [24]2 years ago

7 0

Intro:

Hello!!! Princess Sakura here ^^

Step-by-step explanation:

The quickest way to do this is to look how much it goes down and then how much it goes left. This is called rise over run. So the line goes 2 down then left 3 to get from one perfect point to another.

So the answer is Choice D. It went down 2 so it's negative.

Read more about perimeter at:

brainly.com/question/24571594

3 0

2 years ago

Please help asap!:) Thank you!

finlep [7]

Answer:

(f + g)(3) = 9

Step-by-step explanation:

Given:

f(x) = x² + 1

g(x) = x - 4

Required:

(f + g)(3)

SOLUTION:

✔️Find f(3) by substituting x = 3 into f(x) = x² + 1:

f(3) = (3)² + 1 = 9 + 1

f(3) = 10

✔️Find g(3) by substituting x = 3 into g(x) = x - 4:

g(3) = 3 - 4

g(3) = -1

✔️Find (f + g)(3):

(f + g)(3) = f(3) + g(3)

= 10 + (-1)

= 10 - 1

(f + g)(3) = 9

4 0

2 years ago

Caitlin buys some apples and some oranges. She buys twice as many apples as oranges. Each apple costs £0.25 Each orange costs £0

Vitek1552 [10]

Answer:

Step-by-step explanation:

Caitlin buys twice as many apples as oranges.

$2a=o$

Apples cost 0.25 and Oranges cost 0.30, we have a maximum of 5 to spend.

$5-2a(0.30)-0.25a=0$

$5=2a(0.30)-0.25a\\5=0.6a-0.25a\\5=0.35a\\a=14$

3 0

3 years ago

Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z

kompoz [17]

$f_{X,Y,Z}(x,y,z)=\begin{cases}Ce^{-(0.5x+0.2y+0.1z)}&\text{for }x\ge0,y\ge0,z\ge0\\0&\text{otherwise}\end{cases}$

is a proper joint density function if, over its support, $f$ is non-negative and the integral of $f$ is 1. The first condition is easily met as long as $C\ge0$ . To meet the second condition, we require

$\displaystyle\int_0^\infty\int_0^\infty\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz=100C=1\implies \boxed{C=0.01}$

b. Find the marginal joint density of $X$ and $Y$ by integrating the joint density with respect to $z$ :

$f_{X,Y}(x,y)=\displaystyle\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dz=0.01e^{-(0.5x+0.2y)}\int_0^\infty e^{-0.1z}\,\mathrm dz$

$\implies f_{X,Y}(x,y)=\begin{cases}0.1e^{-(0.5x+0.2y)}&\text{for }x\ge0,y\ge0\\0&\text{otherwise}\end{cases}$

Then

$\displaystyle P(X\le1.375,Y\le1.5)=\int_0^{1.5}\int_0^{1.375}f_{X,Y}(x,y)\,\mathrm dx\,\mathrm dy$

$\approx\boxed{0.12886}$

c. This probability can be found by simply integrating the joint density:

$\displaystyle P(X\le1.375,Y\le1.5,Z\le1)=\int_0^1\int_0^{1.5}\int_0^{1.375}f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz$

$\approx\boxed{0.012262}$

7 0

2 years ago

In a poll, 6 out of 13 children said they read every night before bed, whereas 54% of the adults said they read every night befo

Tpy6a [65]

To answer this question you must find the percentage of the children that read before bed and compare it to the adults bag read before bed’s percentage.
To do this, start by dividing the number of children that read before bed by the total number of children surveyed.
This leaves you with:
6/13= 0.4615

To find the actual percentage, multiply this result by 100.
0.4615 x 100 = 46.15
This percentage rounded is 46%

So, now you can compare the percentages. The percentage of children that read before bed is 46% and the percentage of adults that read before bed is 54%. So, the group with the greatest percentage was the adults.

I hope this helps!

3 0

2 years ago

Will give you brainlyist pls help​

Will give you brainlyist pls help