How many centimeters in 3.7 kilometers
1 answer:
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Unless I am misreading, the question, or don't know all of it, there can be an infinite number of similar shapes. Three are give to you at the bottom of this answer, but there are many more possibilities.
Answer:
- vertical scaling by a factor of 1/3 (compression)
- reflection over the y-axis
- horizontal scaling by a factor of 3 (expansion)
- translation left 1 unit
- translation up 3 units
Step-by-step explanation:
These are the transformations of interest:
g(x) = k·f(x) . . . . . vertical scaling (expansion) by a factor of k
g(x) = f(x) +k . . . . vertical translation by k units (upward)
g(x) = f(x/k) . . . . . horizontal expansion by a factor of k. When k < 0, the function is also reflected over the y-axis
g(x) = f(x-k) . . . . . horizontal translation to the right by k units
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Here, we have ...
g(x) = 1/3f(-1/3(x+1)) +3
The vertical and horizontal transformations can be applied in either order, since neither affects the other. If we work left-to-right through the expression for g(x), we can see these transformations have been applied:
- vertical scaling by a factor of 1/3 (compression) . . . 1/3f(x)
- reflection over the y-axis . . . 1/3f(-x)
- horizontal scaling by a factor of 3 (expansion) . . . 1/3f(-1/3x)
- translation left 1 unit . . . 1/3f(-1/3(x+1))
- translation up 3 units . . . 1/3f(-1/3(x+1)) +3
_____
<em>Additional comment</em>
The "working" is a matter of matching the form of g(x) to the forms of the different transformations. It is a pattern-matching problem.
The horizontal transformations could also be described as ...
- translation right 1/3 unit . . . f(x -1/3)
- reflection over y and expansion by a factor of 3 . . . f(-1/3x -1/3)
The initial translation in this scenario would be reflected to a translation left 1/3 unit, then the horizontal expansion would turn that into a translation left 1 unit, as described above. Order matters.
Answer: The angle of elevation is 18.4 degrees (Approximately)
Step-by-step explanation: Please refer to the picture attached for more details.
The pole from top to bottom is 20 feet tall and is depicted as line FB. An observer is standing at a distance of 20 feet from the base of the pole, and that is depicted as line BA. The observer who is at point A looks up to the top of the flagpole at an angle of elevation shown as angle A.
Using angle A as the reference angle, line FB which is 20 feet would be the opposite (facing the reference angle), while line BA which is 60 feet would be the adjacent (that lies between the right angle and the reference angle).
Therefore, to calculate angle A;
Tan A = Opposite/Adjacent
Tan A = 20/60
Tan A = 1/3
Tan A = 0.3333
Checking with your calculator or table of values,
A = 18.4349°
Rounded to the nearest tenth,
A ≈ 18.4°
