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3 years ago

Is (x+1)/x^2 greater or less or equal to 1/x

Mathematics

1 answer:

Sergio039 [100]3 years ago

6 0

Answer:

(1) x^2 is greater than 1.

(2) x is greater than -1.

(1) x^2 is greater than 1 --> x2>1x2>1 --> x<−1x<−1 or x>1x>1. Sufficient.

(2) x is greater than -1 --> x>−1x>−1. Not sufficient.

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Step-by-step explanation:

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2 years ago

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3 years ago

Value of x for 12(x-2)+3x=1/2(x+6)+2

Damm [24]

Answer:

The value of x = 2

Step-by-step explanation:

Given the equation

$12\left(x-2\right)+3x=\frac{1}{2}\left(x+6\right)+2$

Expand 12(x-2) = 12x - 24

Expand 1/2(x+6) = 1/2x + 3

so the equation becomes

$12x-24+3x=\frac{1}{2}x+3+2$

simplifying

$15x-24=\frac{1}{2}x+5$

$15x=\frac{1}{2}x+29$

multiplying both sides by 2

$30x = x + 58$

subtracting x from both sides

$30x - x = 58 - x$

$29x = 58$

divide both sides by 29

$\frac{29x}{29}=\frac{58}{29}$

simplifying

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3 years ago

If a rectangle has four sides the same length, then it is a square.converse

4vir4ik [10]

The converse of the statement is

if a rectangle doesn't have four sides the same length, then it isn't a square

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3 years ago

Determine whether f(x) = –5x^2 – 10x + 6 has a maximum or a minimum value.

Blizzard [7]

First,

We are dealing with parabola since the equation has a form of,

$y=ax^2+bx+c$

Here the vertex of an up - down facing parabola has a form of,

$x_v=-\dfrac{b}{2a}$

The parameters we have are,

$a=-5,b=-10, c=6$

Plug them in vertex formula,

$x_v=-\dfrac{-10}{2(-5)}=-1$

Plug in the $x_v$ into the equation,

$y_v=-5(-1)^2-10(-1)+6=11$

We now got a point parabola vertex with coordinates,

$(x_v, y_v)\Longrightarrow(-1,11)$

From here we emerge two rules:

If $a$ then vertex is max value
If $a>0$ then vertex is min value

So our vertex is minimum value since,

$a=-5\Longleftrightarrow a$

Hope this helps.

r3t40

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3 years ago