All categories

3 years ago

PLEASE HELP.... i’m so confused on what to do.

Mathematics

2 answers:

KiRa [710]3 years ago

8 0

Answer:

Step-by-step explanation:

Bc they are very diff

(i think )

sesenic [268]3 years ago

3 0

Answer:

Not Similar Because If You Calculate all The Sides Its Not The Same Amount.

Step-by-step explanation:

You might be interested in

Helpppppppppppppppppppppppppppppppppppppppppp

tester [92]

I think the greatest number of students that can be in each row is 18.

you start by finding the highest common factor of 90 and 72

so it means that the teacher will end up with 5 rows of boys and 4 rows of girls with 18 students in each row.

5 0

3 years ago

On Elisa's birthday, her mom made a chocolate cake. After the party,2/3 of the cake was left. The next day, Elisa ate 1/3 of wha

EleoNora [17]

Answer:

1/3

Step-by-step explanation:

when the party started he cake was 3/3 after the party it was 2/3 so they ate one slice/third and now Elisa ate 1/3 one (one Third) so now there is 1/3 left of the cake ( subtracting fractions)

8 0

3 years ago

Read 2 more answers

many colleges determine the number of full time students f,by using the formula f=n/15 where n is the total number of credits fo

Cloud [144]

"A student" doesn't register for 46,140 credits, unless he wants to be very very busy.

If ALL of the students on campus register for 46,140 credits, then many colleges
would estimate the number of full-time students by using the formula

f = n / 15 = 46,140 / 15 = <u>3,076</u> students.

That's not the formula for 'n'. 'n' is the total number of credits for the semester,
and the question tells you what 'n' is. Knowing 'n', the formula helps you find 'f'.

7 0

4 years ago

Calculate the area of triangle ABC with altitude, CD, given

defon

Answer:

37.5 square units

Step-by-step explanation:

Given:

A(-6,-4), B(6,5), C(-1,6), and D(2, 2), where CD is the altitude if ∆ABC

Required:

Area of ∆ABC

SOLUTION:

Area of a ∆ABC =½*AB*CD

✍️ $AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} = \sqrt{6 -(-6))^2 + (5 -(-4))^2$

$AB = \sqrt{12^2 + 9^2}$

$AB = \sqrt{144 + 81}$

$AB = \sqrt{225} = 15$

✍️ $CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} = \sqrt{2 -(-1))^2 + (2 - 6)^2$

$CD = \sqrt{(3)^2 + (-4)^2}$

$CD = \sqrt{9 + 16}$

$CD = \sqrt{25} = 5$

✍️Area of a ∆ABC =½*AB*CD

= ½*15*5

✅ Area = 37.5 square units

5 0

3 years ago

How much more would $1000 earn in 5 years in an account compounded continuously than an account compounded quarterly if the inte

choli [55]

$\bf ~~~~~~ \textit{Compounding Continuously Interest Earned Amount}\\\\
A=Pe^{rt}\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$1000\\
r=rate\to 3.7\%\to \frac{3.7}{100}\to &0.037\\
t=years\to &5
\end{cases}
\\\\\\
A=1000e^{0.037\cdot 5}\implies A=1000e^{0.185}\\\\
-------------------------------\\\\$

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$1000\\
r=rate\to 3.7\%\to \frac{3.7}{100}\to &0.037\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &5
\end{cases}
\\\\\\
A=1000\left(1+\frac{0.037}{4}\right)^{4\cdot 5}\implies A=1000(1.00925)^{20}$

compare both amounts.

8 0

3 years ago