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3 years ago

11

HELP!!! An electronics company designed a cardboard box for its new line of air purifiers. The figure shows the dimensions of th

e box.
The amount of cardboard required to make one box is ___
square inches.

2 answers:

Anarel [89]3 years ago

6 0

Answer:

130 in^2 net area

136 in^2 gross area (counting the 6 in^2 scrap loss for the side cutouts)

Step-by-step explanation:

top=1.5x4=6

middle=1.5x4=6

bottom=3x4=12

sides=(2x3x8)-(2x1.5x2)=42

front & back=2x8x4=64

6+6+12+42+64=130

Lerok [7]3 years ago

5 0

Answer:

A. 130

That's what the other guy said :/

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What could this be! Someone please help

Andrei [34K]

Top one would make more sense

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3 years ago

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Becky d james have a total of 4 2/8 feet of yarn. Becky has 1 5/8 feet of yarn. How many feet of yarn does james have?

ra1l [238]

Let
x----------------> <span>feet of yarn of Becky
y----------------> </span><span>feet of yarn of James

we know that
4 2/8------> 4 1/4--------> (4*4+1)/4-----> 17/4
1 5/8------> (1*8+5)/8-----> 13/5
x+y=4 2/8-------> x+y=17/4----> equation 1
x=1 5/8--------> x=13/5------> equation 2
substitute 2 in 1
[13/5]+y=17/4------> y=(17/4)-(13/5)----> y=[5*17-4*13]/20
y=(85-52)/20-----> y=33/20----> y=1.65-----> y=1 65/100----> y=1 13/20

the answer is
</span><span>james have 1 13/20 ft of yarn</span>

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3 years ago

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katrin2010 [14]

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4 years ago

Papessa [141]

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3 years ago

Which pair of funtions is not a pair of inverse functions? please help!!

antiseptic1488 [7]

Answer:

$f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Step-by-step explanation:

we know that

To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.

we will proceed to verify each case to determine the solution of the problem

<u>case A)</u> $f(x)=\frac{x+1}{6} , g(x)=6x-1$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y+1}{6}$

Isolate the variable y

$6x=y+1$

$y=6x-1$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=6x-1$

therefore

f(x) and g(x) are inverse functions

<u>case B)</u> $f(x)=\frac{x-4}{19} , g(x)=19x+4$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y-4}{19}$

Isolate the variable y

$19x=y-4$

$y=19x+4$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=19x+4$

therefore

f(x) and g(x) are inverse functions

<u>case C)</u> $f(x)=x^{5}, g(x)=\sqrt[5]{x}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=y^{5}$

Isolate the variable y

fifth root both members

$y=\sqrt[5]{x}$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=\sqrt[5]{x}$

therefore

f(x) and g(x) are inverse functions

<u>case D)</u> $f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y}{y+20}$

Isolate the variable y

$x(y+20)=y$

$xy+20x=y$

$y-xy=20x$

$y(1-x)=20x$

$y=20x/(1-x)$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=20x/(1-x)$

$\frac{20x}{1-x}\neq \frac{20x}{x-1}$

therefore

f(x) and g(x) is not a pair of inverse functions

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3 years ago

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