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kodGreya [7K]
3 years ago
10

What is the perimeter of the triangle in the diagram? a + b + a2 + b2 2(a + b)

Mathematics
2 answers:
lesantik [10]3 years ago
8 0
W. A = h(b1 + b2 ). 1. 2 b1 b2 h r h. A = lw p = 2(l + w) l w r c2 = a2<span> + b2 a c </span>b<span> r. 4. 3 h l r. 1. 3. V = Bh ... </span>B.AB<span> line segment </span>AB<span>. </span>AB<span> line </span>AB<span>. </span>AB<span>. ABC </span>triangle<span> ABC. </span>AB<span> measure of line segment </span>AB<span> .... 14 In the Venn </span>diagram<span> below, V represents the set of all vehicles, M represents the set of all .... 39 The ratio of the </span>perimeter<span> of.
39</span>
inn [45]3 years ago
7 0
Where is the triangle?
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Solve for x and identify the type of solution <br><br> 9x=8+5x
Phoenix [80]

Answer:

2

Step-by-step explanation:

9x=8+5x

9x-5x=8

4x=8

x=8/4

x=2

5 0
3 years ago
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Why isn't it possible to divide a factor with 0? And if so, what is the answer? 0? ∞?
zavuch27 [327]

let's think about it, let's divide say hmmm 15 by 0, in a fraction

\bf \cfrac{\textit{part of a pie}}{\textit{whole pie}}\qquad \cfrac{15}{0}\implies \cfrac{\textit{taking 15 pieces}}{\textit{from a whole pie that's 0, or not there}}

now, how can you take any pieces of a pie that's non-existent? I mean that requires magic!!.

now, let's do it using a simple long division, 15 ÷ 0, so 0 is the divisor, anything times 0 is 0, what is our first digit in the quotient to get 15? 0 * 15 = 0, 0 * 1,000,000 = 0, there isn't any number we can possible use to get a quotient.

8 0
3 years ago
Write the equation of the quadratic function whose graph passes through <img src="https://tex.z-dn.net/?f=%28-3%2C2%29" id="TexF
blagie [28]

Answer:

f(x)=x^2+3x+2

Step-by-step explanation:

We want to write the equation of a quadratic whose graph passes through (-3, 2), (-1, 0), and (1, 6).

Remember that the standard quadratic function is given by:

f(x)=ax^2+bx+c

Since it passes through the point (-3, 2). This means that when x=-3, f(x)=f(-3)=2. Hence:

f(-3)=2=a(-3)^2+b(-3)+c

Simplify:

2=9a-3b+c

Perform the same computations for the coordinates (-1, 0) and (1, 6). Therefore:

0=a(-1)^2+b(-1)+c \\ \\0=a-b+c

And for (1, 6):

6=a(1)^2+b(1)+c\\\\ 6=a+b+c

So, we have a triple system of equations:

\left\{        \begin{array}{ll}            2=9a-3b+c &\\           0=a-b+c \\6=a+b+c        \end{array}    \right.

We can solve this using elimination.

Notice that the b term in Equation 2 and 3 are opposites. Hence, let's add them together. This yields:

(0+6)=(a+a)+(-b+b)+(c+c)

Compute:

6=2a+2c

Let's divide both sides by 2:

3=a+c

Now, let's eliminate b again but we will use Equation 1 and 2.

Notice that if we multiply Equation 2 by -3, then the b terms will be opposites. So:

-3(0)=-3(a-b+c)

Multiply:

0=-3a+3b-3c

Add this to Equation 1:

(0+2)=(9a-3a)+(-3b+3b)+(c-3c)

Compute:

2=6a-2c

Again, we can divide both sides by 2:

1=3a-c

So, we know have two equations with only two variables:

3=a+c\text{ and } 1=3a-c

We can solve for a using elimination since the c term are opposites of each other. Add the two equations together:

(3+1)=(a+3a)+(c-c)

Compute:

4=4a

Solve for a:

a=1

So, the value of a is 1.

Using either of the two equations, we can now find c. Let's use the first one. Hence:

3=a+c

Substitute 1 for a and solve for c:

\begin{aligned} c+(1)&=3 \\c&=2 \end{aligned}

So, the value of c is 2.

Finally, using any of the three original equations, solve for b:

We can use Equation 3. Hence:

6=a+b+c

Substitute in known values and solve for b:

6=(1)+b+(2)\\\\6=3+b\\\\b=3

Therefore, a=1, b=3, and c=2.

Hence, our quadratic function is:

f(x)=x^2+3x+2

5 0
3 years ago
What is the relationship between the 6s in the number 7,664
olga55 [171]
The relationship between the 6's in 7,664 is that it can be 600 and 60.
8 0
3 years ago
What number makes the equation true? 27 +_ = 46 ​
shusha [124]

27 + <u> </u><u>x</u><u> </u> = 46

x = 46 - 27

x = 19 <u> </u><u>Ans</u><u> </u> .

4 0
3 years ago
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